Page 61 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

53
1. !!" # $
%&

- ก! 1.15 g 6 mS " , F = 1 kHz + ก ,
m

F = 400 MHz -( g = 4 mS
m
- ก 1.45 0 0 j (+ g ก0,ก ( I " g m
m
D
80 ! ก0,ก ( I '(& 0 :-
D
− & ก ) T = 25 C g = 6 mS, I = 10 mA; '( ! *

m
D
A
g = 0.6 mS, I = 0.1 mA;
m
D
− & ก ) T = 125 C g = 5.4 mS, I = 10 mA; '(

A m D
! * g = 0.4 mS, I = 0.1 mA;
m
D
− & ก )T = − 55 C g = 7 mS,I = 10 mA; '(

D
A
m
! * g = 1 mS,I = 0.1 mA;
m
D
ก $& (+ '( ก ,,-( g - * / &)! (
m
- ก ก

2I DSS
g m 0 = (1.18)
V P
 V 
g = g 1− GS  (1.19)
m m 0 
 V P 
0 0
" g
ก ! % / ( V =
m 0 GS
- ก 1.46 0 0 j (+ ก ( I ก0, V &
0
D GS
ก* + I = 5 mA -( - * '(& 0 :-
D
10
V DS = 10 V,V GS (off ) = − 3 V;
8 T = − 55 C
-Drain Current (mA) 6 4 T = D 25 C GS = − 1.05 V;

A

A
I =
5 mA,V

A
D T = 125 C
I
2
− 1.05
0
0 − 0.6 − 1.2 − 1.8 − 2.4 − 3
V GS -Gate-SourceVoltage (V)

1.46 0 0 j (+ ก ( I ก0, 0 V
D GS
ก

ก
ก