Page 80 - 30105-2003 การวิเคราะห์วงจรอิเล็กทรอนิกส์ความถี่สูง

72
2.

R FLCB = R + Z
BB
g
E = I i ( R + X C B ) + I Z
g
i BB
g
 1 
E = I R + + I Z
g i  g  i BB
ω
 J C B 
ω
+
 1  { 1 J C B ( R + Z BB )}
g
E = I i  R + Z BB +  = I i
g
g
ω
ω
 J C B  J C B
ω
E J C B
g
I = { 1 J C B ( R + Z BB )}
i
ω
+
g
I R
I =
i BB
b
( R BB + r bb′ + r b e ′ )
ω
E J C B R
g
I = × BB
{ 1 J C+ ω B ( R + Z BB )} ( R BB + r bb′ + r b e ′ )
b
g
V = g V Z
′
o
m b e out
ω
E g Z J C r R
′
B b e BB
g m out
V =
{ 1 J C B ( R + Z BB )}( R BB + r bb′ + r b e ′ )
o
+
ω
g
ω
V o g Z J C r R
′
B b e BB
m out
A = − = −
V (F L )
ω
+
E g { 1 J C B ( R + Z BB )}( R BB + r bb′ + r b e ′ )
g
X C B = R FLCB = R + Z
g
BB
1 1
-
(
- ก X C = . = ( R + Z BB )
g
B ω C B ω C B
1
Cω B =
( R + Z BB )
g
1
ω
%
Cω B =
J C
B
( R + Z BB )
g
V o J ( g r Z R ) 1
′
m b e out BB
A = − = − ×
V (F L ) )

E g  ( R + Z BB )  ( R + Z BB

g
g
+
 1 J  ( R BB + r bb′ + r b e ′ )
 ( R + Z BB ) 


g
V o J g r Z R )
′
( m b e out BB
A V (F ) = − = −
+
L
E g {1 J 1 }( R BB + r bb′ + r b e ′ )( R + Z BB )
g
( g r Z out R BB ) 90
m b e ′
A V (F ) = −
1
L  2 2 − 1 
( R BB + r bb′ + r b e ′ )( R + Z BB )  ( ) 1 + ( ) 1 tan 
g
 1 
V o ( g r Z R BB ) 90
′
m b e out
A V (F L ) = − = −
E g ( R BB + r bb′ + r b e ′ )( R + Z BB ) 2
45
g
ก

ก
ก