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_
L

B =

CHAPTER 10 4πd 2
Example 10.2, p. 253 Convert light years to meters.
Atoms Atomic Weight Totals 12 3
(
)(
9.5 × 10 km _

2 of C 2 × 12.0 u 24.0 u d = 8.6 ly __ 1 × 10 m )

1 km
1 ly
6 of H 6 × 1.0 u 6.0 u
ly
_
m _
km
3 _
1 of O 1 × 16.0 u 16.0 u = 8.6(9.5 × 10 )(1 × 10 ) × ×
12

46.0 u 1 ly km
16
= 8.2 × 10 m
28
Example 10.4, p. 254 __
1.1 × 10 W

B = 16

2
1. Formula: C 12 H 22 O 11 4π(8.2 × 10 m)
2. Formula weight 28
1.1 × 10
__ W _

12 of C 12 × 12.0 u = 144.0 u = 4π(8.2 × 10 ) m 2
16 2
22 of H 22 × 1.0 u = 22.0 u 28
_ W _
1.1 × 10

11 of O 11 × 16.0 u = 176.0 u = 34
2
8.4 × 10 m
342.0 u
−7 W _
= 1.3 × 10

3. Percentage of carbon m 2
(12.0 u)(12)
__
×

342.0 u 100% C 12 H 22 O 11 Example 14.5, p. 357
This problem is solved by determining the temperature of the star and
_ × 100% = 42.1% then referring to Table 14.2 to determine its type.
144 u

342.0 u
λ peak = 5,050 angstroms
CHAPTER 11 T = ?
7
2.897 × 10 K ⋅ angstroms
__

Example 11.2, p. 282 T =

λ peak
% solute = 0.002% 7
2.897 × 10 K ⋅ angstroms
V solution = 100,000 L = __

5,050 angstroms
_
V solute

× 100% solution = % solute 7
2.897 × 10 K ⋅ angstroms

=
V solution _ __
5,050 angstroms
(V solution )(% solute)
__ 3

∴ V solute = = 5.74 × 10 K
100% solution
= 5,740 K
__
(100,000 L)(0.002%)

=
100% solution Referring to Table 14.2, this would be a type G star that is yellow.
_
200 L

=
100 CHAPTER 15
= 2 L Example 15.2, p. 387
The relationship between heat supplied, the mass of the ice, and the
CHAPTER 13 temperature change is equation 4.4 in chapter 4. The specific heat of
ice is in Table 4.2. Determine the heat needed to raise the temperature
Example 13.2, p. 326 of the ice to its melting point, and compare to the energy received
226 4 222 from the Sun. If there is excess energy from the Sun, use the latent
88 Ra → 2 He + 86 Rn
heat relationship Q = mL f to determine the mass of the ice that melts.
First, determine the mass of the ice:
CHAPTER 14
7
6
2
V ice = (3.5 × 10 cm )(20 cm) = 7.0 × 10 cm 3
Example 14.3, p. 356 g
_
28

L = 1.1 × 10 W ρ ice = 0.917

cm 3
d = 8.6 ly
m ice = ?
B = ?
D-5 APPENDIX D Solutions for Follow-Up Example Exercises 637