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• = along horizontal (a=0)
• = along vertical (a = g)
• The horizontal motion of the projectile is uniform (a = 0) and the vertical
motion is accelerated ( a = g)
Equation of path:
Let P be the position of projectile at any time t. During this time, the projectile has
covered horizontal displacement x and vertical displacement y.
For horizontal motion:
1
2
= +
2
= ( ) … … … ( )
For vertical motion:
1
2
= +
2
1
2
, = ( ) + (− ) … … … ( )
2
Eliminating t from equation ( ) ( )
1 2
= ( ) + (− ) ( )
2
2
= − ( )
2
2
2
This is the required equation of path. It shows that the path followed by a projectile
is parabolic in nature.
Velocity at any instant t:
Let P be the position of projectile at any time t. The velocity v at the point P can
be resolved into horizontal component and vertical component as shown in
figure.
For horizontal motion, = =
For vertical motion, = + = + (− ) = −
20 Mechanics

