Page 12 - PBD Plus Matematik Tambahan T4 (EG)
P. 12

Matematik Tambahan  Tingkatan 4  Bab 1 Fungsi
              SP 1.2.3  Menentukan imej suatu fungsi gubahan apabila objek diberi dan sebaliknya.
                                        x – 1            1
               8.  Diberi dua fungsi f : x →     dan g : x →  .   TP 3
                                          2              x
                                        x – 1        1
                  Given the two functions f : x →     and g : x →   .
                                         2           x
                        Contoh
                                                                    (a)  (i)  Cari gf(–1). / Find gf(–1).
                   (i)  Cari fg(2).                                                                1
                                                                                             2
                      Find fg(2).                                      (ii)  Cari nilai x apabila f  (x) =   .
                                                                                                   2
                                                                                                  1
                   (ii)  Cari nilai x apabila g (x) = 5.                   Find the value of x when f  (x) =   .
                                         2
                                                                                             2
                                         2
                      Find the value of x when g (x) = 5.                                         2
                   (i)  fg(x)              (ii)  gg(x)              (i)  gf(x) = g  x – 1     (iii)  ff(x) = f   x – 1 
                                                   1
                          1
                                                                                                         2
                      = f                    = g                            1 2                   x – 1
                          x
                                                   x
                          1  – 1           	   =   1                	 	     =  x – 1                =   2   – 1
                                                                                                         2
                   	  =   x  2                   1                          =  2                    =  x – 1 – 2
                                                                               2
                                                 x
                                    Penerbitan Pelangi Sdn. Bhd.
                      =  1 – x , x ≠ 0         = x                            x – 1                      4
                          2x                    gg(x) = 5              ∴ gf(–1) =   2               =  x – 3
                      ∴ fg(2) =  1 – 2             x = 5                          –1 – 1                4
                                                                                                        1
                                2(2)                                            = –1               ff(x) =
                                                                                                        2
                             = –  1                                                              x – 3  1
                                 4                                                                4   =
                                                                                                        2
                                                                                                    x = 5
              SP 1.2.4  Menentukan suatu fungsi berkaitan apabila fungsi gubahan dan salah satu fungsinya diberi.
               9.  Nyatakan fungsi f bagi setiap yang berikut berdasarkan fungsi g dan fungsi gubahan yang diberikan.  TP 4
                  State the function f of each of the following based on the given function g and the composite function.
                        Contoh
                   (i)  g(x) = x − 6 dan / and gf(x) = x − 3.       (ii)  g(x) = x + 5 dan / and fg(x) = 2x + 15.

                        gf(x) = x – 3                                  Katakan / Let y = g(x)
                        f(x) – 6 = x – 3                                           y = x + 5
                          f(x) = x + 3                                             x = y – 5
                                                                                fg(x) = 2x + 15
                                                                                 f(y) = 2(y – 5) + 15
                                                                                     = 2y – 10 + 15
                                                                                     = 2y + 5
                                                                                 f(x) = 2x + 5


                   (a)  g(x) = x + 9 dan / and gf(x) = x − 7.       (b)  g(x) = 2x – 5 dan / and fg(x) = 2x + 1.

                        gf(x) = x – 7                                  Katakan / Let          fg(x) = 2x + 1
                        f(x) + 9 = x – 7                               y  = g(x)               f(y) = 2  y + 5   + 1
                          f(x) = x – 16                                y  = 2x – 5                      2
                                                                       x  =    y + 5               = y + 6
                                                                              2                f(x) = x + 6


                   (c)  g(x) = 5x + 7 dan / and gf(x) = 3x − 1.     (d)  g(x) = 3x + 1 dan / and fg(x) = 3x + 2.
                           gf(x)  = 3x – 1                             Katakan / Let          fg(x) = 3x + 2
                      5[ f(x)] + 7  = 3x – 1                           y  = g(x)               f(y) = 3   y – 1   + 2
                            f(x)  =  3x – 8                            y  = 3x + 1                      3
                                    5                                  x  =    y – 1               = y + 1
                                                                              3                f(x) = x + 1




              TAHAP PENGUASAAN  1  2  3   4   5   6             5                            © Penerbitan Pelangi Sdn. Bhd.
   7   8   9   10   11   12   13   14   15   16   17