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Mathematics Term 1  STPM  Chapter 2 Sequences and Series
               6.  Find the geometric mean of each of the following numbers.

                 (a)  3 and 27                (b)   1  and   1             (c)  10  and 10 27
                                                                                 3
                                                   3     27
               7.  Given that the geometric mean of 4p – 3 and 9p + 4 is 6p – 1, find the values of p.
               8.  The second and fifth terms of a geometric series are 405 and –120 respectively. Find the seventh term
                 and the sum of the first seven terms of the series.
               9.  In a geometric progression, the second term exceeds the first term by 20 and the fourth term exceeds the
                 second term by 15. Find the possible values of the first term.

                                                        1
                                                            1
                                                                3
         2    10.  Find the sum of the first n terms of the series  12  +   +   +  … . Find also the number of terms required
                                                            4
                                                                4
                 such that the sum exceeds 100.
              11.  A geometric series has first term 16 and common ratio   3   . If the sum of the first  n terms exceeds 60,
                 find the smallest value of n.                   4
             Sum of an infinite geometric series

             When the number of terms of a geometric series is infinite, it is called an infinite geometric series.
             Consider the infinite geometric series
                                                 1
                                1 +   1  +   1  +  …  +  1 2   n – 1  +  …
                                    2   4        2
             The sum of the first n terms is
                                         1
                                           n
                                    3
                                   1 1 –  1 2 4
                             S   =       2
                              n
                                     1 –   1
                                         2
                                        1
                                          n
                                   3
                               = 2  1 –  1 2 4
                                        2
                           1
             As n increases,   1 2 n  → 0 and S  → 2.
                                       n
                           2
                                                                     lim
                                                                         S  = 2.
             We say the limit of S  as n → ∞ exists and equals 2, and we write  n → ∞  n
                              n
             This series is called a convergent series with a sum of 2. Notice that the common ratio is   1   , 1.
                                                                                        2
             We now consider the infinite geometric series
                                               1 + 2 + 4 +  …  + 2  +  …
                                                               n
             The sum of this series is infinite.
             This series is called a divergent series.
             In general, for a geometric series with first term a and common ratio r,
                                      n
                           S   =   a(1 – r )
                            n
                                  1 – r
                              =   a   –  1  a  2  r  n
                                1 – r   1 – r




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       02 STPM Math T T1.indd   108                                                                    3/28/18   4:21 PM
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