Page 15 - Steady Matematik 2021 TG2 Buku B
P. 15
JAWAPAN
KANDUNGAN
I 1. (x + 1)(x + 3) 2. (x + 1)(x + 4)
BAB Pemfaktoran dan Pecahan Algebra 3. (x – 1)(x – 3) 4. (x – 1)(x – 4)
2 Factorisation and Algebraic Fractions 5. (x + 3)(x – 8) 6. (x + 3)(x – 7)
7. (x + 1)(2x + 3) 8. (x + 3)(2x + 1)
9. (2x – 1)(6x + 5) 10. (12x – 7)(x + 2)
A 1. 2a – 8 2. –12 + 8t 11. (–3x + 2)(x + 1) 12. (–2x – 1)(x – 2)
3. 3p – 6pq 4. x + xy J 1. (3x + 4) m
2
2
3
2
5. 3m – 6m 6. –g – 2gn + gh
2
rs Praktis Berformat PT3
KANDUNGAN
7. –3x + 6xy 8. 4r – r –
2
2
3
1 B 1. x + 3x + 2 2. x + 9x + 20 1. C
2
2
=
2 3. x + x – 6 4. x + 4x – 5 2. B
2
2
2
2
5. x + 4x – 12 6. x + 6x – 7 3. 2y + y – 21 = (2y + 7) (y – 3)
2
7. x – 5x + 6 8. x – 10x + 24
2
2
2
9. 12w – w – 1 10. 9a – 3a – 2 2y +7 7y
2
11. 4k + 4k +1 12. 4y – 16y + 16
2
2
y –3 –6y
C 1. x – 10xy + 9y 2. 2pq – q 2 2y 2 –21 +y
2
2
3. 11k – 1
4. (a) (i) 4x(1 + 3x) (ii) 6(y – 3)
D 1. RM(73 – 2km + k + 4m) (iii) (2y – 3)(5y + 4)
2. 13x − 34x + 25 cm (b) 1, 3, n dan/and 3n. 2
2
(c) (5x + 10x + 4) cm
2
3. y + 10y + 20
2
3a
e
K 1. 2. 3b 3. 5f
5
4
Praktis Berformat PT3 g 2l + 9 n + 2
KANDUNGAN
4. 5. 6.
3h m 2 p
1. D 7. r 8. s 9. 7
2. B 6 14 3v
5
3. 10. 2wx 11. 3a + b 12. 5f – 23
4ef
2c
15i – 4k 9ln + 2m 17
13. 14. 15. –
10 6n 18q
ru + u – st
16.
s u
2
cd 15g
L 1. 2.
3e fh
2k 3p
3. 4.
4. (a) (i) –6p + 4q (ii) –3j + 9j m 2n
2
(iii) m n – 2m 2 rs (t + 1)(u + 1)
2
(b) (i) 11k – 8k – 10 (ii) m + n 5. (s – 2)(r + 5) 6. (2t – 3u)(3u + 46)
2
2
2
(c) 20p + 500 2 5
7. 8.
E 1. 1, 2, 4, p, 2p dan/and 4p x(y – 1) 1 – 2z
2. 1, x, y, z, yz, xz, xy dan/and xyz 8d 8ef
M 1. 2.
F 1. 1, 2, 4, k, 2k dan/and 4k. 9c 5
2. 1, 5, m dan/and 5m. 5k m
3. 4.
G 1. 6g 2. rs 8j 3l
3. 2t 5. p(q – 2) 6. 3r(s – 4)
q(q – 1) 5s(s + 3)
H 1. 3(2a – 3) 2. 4(2a – 3) v 1
3. 3(k + 2l + 3m) 4. 4x(1 + 3y – 5x) 7. 4w 2 8. yz
5. (a – b)(2 – c) 6. (f + g) (2e + 1)
7. (x + 5)(x – 5) 8. (x + 7)(x – 7) N 1. 2d(c + 3d)
9. (4c + 5)(4c – 5) 10. (7c + 8)(7c – 8) (c – 3d)(4c + 3d)
11. 5(p + 4)(p – 4) 12. 4(2k + 3p)(2k – 3p) O 1. 2(k + 6) cm
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