Page 9 - Steady Matematik 2021 TG2 Buku B
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Matematik  Tingkatan 2  Bab 4 Poligon

            G    Cari nilai x bagi setiap poligon yang berikut.   TP 3   ARAS S
                Find the value of x for each of the following polygons.

              Contoh                           1.                                2.
                                                                    100°                         80°
                                                       150°                                            x
                             100°
                                                                    x                     140°        60°


                                  x
                    140°


                                                  x + 100° + 150° = 360°          x + 80° + 140° + 60° = 360°
            x + 100° + 140° = 360°                                                          x + 280° = 360°
                                                        x + 250° = 360°
                 x + 240° = 360°                                                                   x = 360° − 280°
                                                              x = 360° − 250°
                        x = 360° − 240°                                                             = 80°
                                                                = 110°
                         = 120°
              Contoh                           3.                                4.        85°          x
                                                                   x


                             x                                                                    110°

                      150°   50°                          130°    80°                      100°




                                                  x + 130° + 100° = 360°          x + 85° + 100° + 70° = 360°
            x + 150° + 130° = 360°                      x + 230° = 360°                     x + 255° = 360°
                 x + 280° = 360°                              x = 360° − 230°                      x = 360° − 255°
                        x = 360° − 280°                         = 130°                              = 105°
                         = 80°

              Contoh                           5.                                6.

                                                                    x
                         x
                                x                        x           50°                       x


                                                          65°       75°
                   100°         x
                         50°

                                               x + x + 65° + 75° + 50° = 360°        5x = 360°
            x + x + x + 50° + 100° = 360°                 2x + 190° = 360°              360°
                      3x + 150° = 360°                          2x = 360° − 190°        x =   5
                            3x = 360° − 150°                       = 170°              = 72°
                            3x = 210°                               170°
                                210°                             x =
                             x =                                     2
                                  3                              x = 85°
                             x = 70°


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     Bk B_04 Steady Mate Tg2.indd   22                                                                        24/03/2021   5:26 PM
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