Page 41 - Steady Mate Tg1 - Book A

Matematik Tingkatan 1 Bab 5 Ungkapan Algebra

B Tulis satu ungkapan bagi setiap situasi yang berikut. TP 2 ARAS R
Write an expression for each of the following situations.

Contoh 1. Tambah 7 kepada q. 2. Tolak 5 daripada 3x.
Add 7 to q. Subtract 5 from 3x.
Tambah 4 kepada p.
Add 4 to p.
q + 7 3x – 5
p + 4

Contoh 3. Hasil darab 3 dan z, kemudian 4. Hasil tambah h dan 2 dibahagi
tolak 8. dengan 9.
Hasil darab 2 dan y, kemudian tambah The product of 3 and z, then minus 8. The sum of h and 2 divided by 9.
8.
The product of 2 and y, then plus 8. h + 2
3z – 8
2y + 8 9

Contoh 5. Jumlah kos bagi m kg betik 6. Wang baki yang diterima oleh
dengan harga RM6.50 per kg Zul selepas dia membayar RM25
Jumlah kos bagi x biji epal dengan dan n kg tembikai dengan harga untuk k batang pen yang berharga
80 sen sebiji dan y biji oren dengan RM1.20 per kg. RM4 sebatang.
60 sen sebiji. Total cost of m kg of papaya The balance Zul received after paying
Total cost of x apples at 80 sen each and costing RM6.50 per kg and n kg of RM25 for k pens which cost RM4 each.
y oranges at 60 sen each.
watermelon costing RM1.20 per kg.
80x + 60y 6.5m + 1.2n 25 – 4k

C Diberi a = 3, b = 2 dan c = – 4, cari nilai bagi setiap ungkapan algebra yang berikut. TP 2 ARAS R
Given that a = 3, b = 2 and c = – 4, find the value for each of the following expressions.

Contoh 1. 5a + 2b = 5(3) + 2(2) 2. 8a – b = 8(3) – 2
= 15 + 4 = 24 – 2
4a + b = 4(3) + 2 = 19 = 22
= 12 + 2
= 14
Contoh 3. 3a + 6b – c = 3(3) + 6(2) – (– 4) 4. 2a – 4b – 3c = 2(3) – 4(2) – 3(– 4)
= 9 + 12 + 4 = 6 – 8 + 12
a + 3b – 2c = 3 + 3(2) – 2(– 4) = 25 = 10
= 3 + 6 + 8
= 17
Contoh 5. 7(a + c) = 7[3 + (– 4)] 6. 3(a – c) = 3[3 – (– 4)]
= 7(–1) = 3(7)
2(a + b) = 2(3 + 2) = –7 = 21
= 2(5)
= 10
Contoh 7. a + 2b – 4c = 3 + 2(2) – 4(– 4) 8. 9a – b + 3c = 9(3) – 2 + 3(– 4)
3 3 4 4
c – 4
+ 5a – b = + 5(3) – 2 = 1 + 4 + 16 1
2 2 = 21 = 27 – 2 – 12
= –2 + 15 – 2 1
= 14
= 11 2

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