Page 14 - Praktis Hebat 2021 - Mathematics F5

Mathematics Form 5 Answers

12
10. (a) 1 2 (b) w = –3, x = –2 PRACTICE Consumer Mathematics: Insurance
10
4
11. (a) W = 1 –5 –2 2 3 Matematik Pengguna: Insurans
3
(b) Fares for an adult PAPER 1
Tambang untuk seorang dewasa 1. B 2. C 3. D 4. D 5. C
= RM5.00 6. C 7. C 8. C 9. B 10. C
Fares for a child
1 Tambang untuk kanak-kanak PAPER 2
= = RM2.00
2 1.
12. (a) k = –18, l = –7 (a) 3
(b) m = 2, n = 6 (b)
√22 – 11 2 3
2
13. (a) m = –5, n = 9 (c)
1
x
Z (b) 1 9 5 21 2 1 2 ; x = 4, y = –7 2. RM640 000
=
2
–2
3
y
14. (a) m = –13, n = –2 3. (a) RM1 176
(b) RM720
x
4
=
(b) 1 5 –1 21 2 1 2 ; x = 2, y = 6 4. (a) RM1 180
–14
y
–3
2
2 –1 (b) RM530.50
(c) RM15
15. (a) 5 3 2
1 – 5. (a) RM1 560.65
4 4
(b) The third party, fire & theft policy is cheaper by
(b) The price of a blue pen RM413.57.
Harga sebatang pen biru Polisi pihak ketiga, kebakaran & kecurian lebih
= RM2 murah sebanyak RM413.57.
The price of a black pen 6. (a) Required amount of insurance
Harga sebatang pen hitam Jumlah insurans yang harus dibeli
= RM1.50 = 0.8 × RM1 000 000
16. x = RM8, y = RM11.25 = RM800 000
17. (a) x + y = 12; 40x + 38y = 470 RM650 000 , RM800 000
(b) x = 7, y = 5 Compensation / Pampasan
18. x = 30, y = 90 = 1 RM650 000 × RM63 900 2 – RM38 000
RM800 000
1 2 3 21 2 1 2 = RM51 918.75 – RM38 000
15
x
19. (a) 3 5 y = 24 = RM13 918.75
The price of the chocolate, x The company can make a claim for partial
Harga coklat, x compensation.
= RM3 Syarikat tersebut hanya boleh menerima
The price of the cookies, y pampasan separa.
Harga biskut, y (b) The company did not fulfil the 80% required
= RM3 amount of co-insurance. They have under-insured
(b) Yes, "Hamper Super" is more worthwhile than their building, that is, only 65% of the value of
the other two hampers because the price is RM4 the building and therefore, bear a co-insurance
cheaper than the original price. penalty of 35%. They do not qualify for full
Ya, “Hamper Super” lebih berbaloi kerana compensation.
harganya RM4 lebih murah daripada harga asal. Syarikat tersebut tidak memenuhi peruntukan ko-
insurans sebanyak 80%. Mereka telah terkurang
HO TS Practices menginsuranskan bangunan iaitu hanya 65%
TS
HO
HOTS
Practices
daripada nilai boleh insurans bangunan dan
1 3 – 5 2 terpaksa menanggung penalti ko-insurans
sebanyak 35%. Mereka tidak layak untuk
1. (a) M = 2 2 menerima pampasan penuh.
–1
–1 2
HO
HOTS
TS
(b) The price of a cupcake A HO TS Practices
Practices
Harga sebiji kek cawan A 1. 70%
= RM5
The price of a cupcake B
Harga sebiji kek cawan B
= RM1
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ANS HEBAT MATH F5.indd 2 28/04/2021 5:36 PM