Page 11 - TOP ONE MATHS F3
P. 11

Top One (MATHS F3) Penerbitan Pelangi Sdn Bhd




 CHAPTER  Indices  Mathematics  Form 3  Chapter 1  Indices     9.  (a)  8  =  8  = 2  (b)  2  × 8  × 32 –2n  5 –2n
          Mathematics  Form 3  Chapter 1  Indices
                                                                      2n
                                                                 4n
               1
 1
               3
                    3
                                                                   4n

                                                                = 2  × (2 )  × (2 )
                                                                         3 2n
                                                                             –10n
                                                                        6n
                                                                   4n
 Indeks
                1
                                                                = 2
                                                                   4n + 6n – 10n
                4
                      4
          (b)  16  =   16  = 2                                = 2  × 2  × 2
                                                                = 2 0
                                                                = 1
                3
                          3
                4
          (c)  16  = (16)  =   8
                     4
   1.  (a)  False  5  2  10  7  3                                1    1    1
 (b)  True    5.  (a)  3  ÷ 3  3  3  3  2                  (c)  2  × 5  × 10 2
                                                                 2
                                                                      2
                              2
 (c)  False  5  3  2  15  8  (d)  216  =    (216)  = 36          1    1         1
                        3
                  3

                                                                   2
                                                                        2
 (d)  True  (b)  7  ÷ 7  7  7  7                                = 2  × 5  × (2 × 5) 2
                                                                     1
                                                                    +
 (e)  False                                                        1 2     2    1 2     2 1
                                                                            +
 (c)  2  ÷ 2 3  2 11  2 5  8 24  (e)  3  =   1   =   1          = 2     × 5
 8
               –3
   2.  (a)  2 4  27  3 3    27                                  = 2 × 5
 (d)  m  ÷ m 8   m 17  m 2  m                                   = 10
 9
                          1
 1
               –4
 (b)     2  729  (e)  h  ÷ h 4  h 16  h 8  h 3  (f)  2  =   2 1 4  =   16
 12
 8
                                                                   –   1  3
                                                                64  3  × 9 2
 (c)  3 3  1      0                                        (d)     4 –3
 64    6.  (a)  ✓  (g)  (–9)  =   1                                    1     3
 (b)  ✗                                                           (4 ) –   3  × (3 )
                                                                           2 2
                                                                    3
 (d)  9    16  (c)  ✗  0                                        =      4 –3
 3
                1
 (d)  ✓   (h)        = 1                                            1          3
 4
 (e)  5    625  10                                                 3 × –    – (–3)  2 ×    2
                                                                      3
 (e)  ✗                                                         = 4        × 3
                                                                = 4  × 3 3
                                                                   2
   3.  (a)  125 = 5 × 5 × 5 = 5    3  × 3 8
 3
               –4
   7.  (a)  (5 × 2) 2   10.  (a)                                = 16 × 27
 2
 (b)  36 = 6 × 6 = 6    3 –3
    = 5  × 2 2   –4 + 8 – (–3)                                  = 432
 2
 (c)  1 000 000 = 10 × 10 × 10 × 10 × 10 × 10   (b)  (6 × 2) 3     = 3
 = 10       = 6  × 2       = 3 7                                          2
 6
 3
 3
 3
 2 5
 (d)  64 = 8 × 8 = 8 2  (c)  (8  × 9 )    2 × 5  12p q     (e)   27 –   2 3  × 64 3
                  3 5
  × 9
 3 × 5
 = 8

 1
 1
 1
                2 –4 –6
 (e)     2  =   1   ×   =    2     = 8  × 9 10  (b)   2 p q      3 –   –4 2  2
 15
 6
 6
 36
 6
                                                                    3
                                                                           3 3
 4
 (d)  (6  × 5 )       =   12  × p 3 – (–4 )q 5 – (–6)           =   (3 )  3  × (4 )
 5 4
 3
   4.  (a)  2  × 2       = 6 4 × 4  × 5 5 × 4  4                       3 –4
 2
                  7 11
                                                                      2
         = 2 2 + 3       = 6  × 5 20     = 3p q                 = 3 3 × –   – (–4)  × 4 3 ×  2 3
 16
                                                                      3
         = 2 5  (e)  (3  × 4  × 5) 3                            = 3  × 4 2
 2
 3
                                                                   2
 (b)  6 × 6       = 3 3 × 3  × 4 2 × 3  × 5 1 × 3  (c)   m n  × m –3     = 9 × 16
                9 –3
 2
 6
 9
                   5 –2
    = 6 1 + 2        = 3  × 4  × 5 3  m n                       = 144
                      n
    = 6 3     = m 9 – 3 – 5 –3 – (–2)
 4 2
 5
   8.  (a)  3  × (3 )  ÷ 3 9     = mn –1
 (c)  4  × 4    5 + 4 × 2 – 9
 7
 3
                                                                         1
    = 4 7 + 3        = 3 4     =   m                       (f)   1   × (8 )  ÷ 8
                                                                        3 2
    = 4 10     = 3  n                                           	8
 (b)  8  × 8  ÷ (8 )                                                1    1
 3 2
 3
 7
 4
 (d)  5  × 5    7 + 3 – 3 × 2  3  –   1  –   3                  = 8 –    + 3 ×   – 1
 8
                                                                    2
                                                                         2
                     2
               2
    = 5 8 + 4        = 8 4   11.  (a)  3  × 5  × 15  2             –    +   – 1
                                                                    1
                                                                      3
                                                                    2
                                                                      2
    = 5 12     = 8  3 2  –   1 2  –   3 2                       = 8
 5 2
 (c)  (m )  × (m )  ÷ (m )     = 3  × 5  × (3 × 5)              = 8 0
 3 4
 2 8
 7
 6
 (e)  w  × w    3 × 4 + 5 × 2 – 2 × 8  3  –   3  –    –   3     = 1
                         1
    = w 7 + 6     = m 12 + 10 – 16     = 3 2   2  × 5  2  2
                 0
    = w 13     = m     = 3  × 5 –2
    = m 6           1
              = 1 ×
                    5 2
          	   =   25
                 1
 1  © Penerbitan Pelangi Sdn. Bhd.  © Penerbitan Pelangi Sdn. Bhd.  2
 A2
 BOOKLET ANS MATH F3.indd   2                                                             03/01/2020   10:20 AM
   6   7   8   9   10   11   12   13   14   15   16