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                 Mathematics  Form 3  Chapter 2 Standard Form

                 (b)  Express 0.000045 in standard form.   2.2.1          Answer / Jawapan:
                    Ungkapkan 0.000045 dalam bentuk piawai.                      5.43       5.43
                                           [1 marks / 1 markah]           (i)            =
                                                                              30.1 – 0.54  29.56
                    Answer / Jawapan:                                                    = 1.84 × 10 –1
                            –5
                    4.5 × 10
                                                                                       2
                                                                          (ii)  (6.09 × 10 ) ÷ (2.31 × 10 )
                                                                                                    –3
                                                                             = 6.09 ÷ 2.31 × 10 2 – (–3)
               2.  (a)  Round off 299 530 correct to three significant         = 2.64 × 10 5
                    figures.                             2.1.2
                    Bundarkan 299 530 betul kepada tiga angka bererti.
                                           [1 marks / 1 markah]       (c)  (i)  A water fall has a width of 2 356 m, write
                    Answer / Jawapan:                                        the width in standard form.      2.2.1
                       +1                                                    Suatu air terjun mempunyai lebar 2 356 m, tulis
                    299 530  300 000                                        lebar itu dalam bentuk piawai.
                                                                                                 [1 mark / 1 markah]

                                                                             Answer / Jawapan:
                                                                                              3
                 (b) Fill in the blanks.                 2.2.2               2 356 = 2.36 × 10  m
                    Isi tempat kosong.
                                           [3 marks / 3 markah]
                     Answer / Jawapan:                                    (ii)  It is estimated that by the year 2060, the
                                                                             world population will exceed k billion. If
                                          –9
                    0.000000085 ÷ 1.7 × 10                                   the world population in the year 2060 is
                                                                                      11
                                                                             1.05 × 10 , find the value of k.     2.2.3
                    =   8.5 × 10 –8   ÷ 1.7 × 10 –9                          Jumlah bilangan penduduk dunia dijangka akan
                                                                             mencapai k billion pada tahun 2060. Jika jumlah
                    = 8.5 ÷ 1.7 × 10 –8 +   9                                penduduk  dunia  pada tahun  2060 ialah  1.05  ×
                                                                             10 , cari nilai k.
                                                                               11
                    =   50                                                                       [2 marks / 2 markah]
                                                                             Answer / Jawapan:
                                                                               1.05 × 10  = k × 10
                                                                                               9
                                                                                      11
             Section C/ Bahagian C                                                    k = 1.05 × 10  billion
                                                                                                  2
                                               k
               1.  (a)  Given 69 350 000 = 6.935 × 10  and 0.00000123                               –1
                              l
                    = 1.3 × 10 , find the value of k × l.   2.2.2    2.  (a)  The speed of a car is 75 kmh . At this speed,
                    Diberi 69 350 000 = 6.935 × 10  dan 0.00000123 = 1.3 × 10,     find the distance, in m, travelled by the car in 9
                                         k
                                                             l
                    cari nilai bagi k × l.                                000 seconds. Express your answer in standard
                                           [3 marks / 3 markah]           form.                               2.2.3
                                                                          Kelajuan sebuah kereta ialah 75 kmh .  Pada kelajuan
                                                                                                     –1
                    Answer / Jawapan:                                     ini, cari jarak, dalam  m, yang dilalui oleh  kereta itu
                     k = 7, l = –6                                        dalam masa 9 000 saat. Nyatakan jawapan anda dalam
                                                                          bentuk piawai.
                    ∴ k × l = 7 × (–6) = –42
                                                                                                 [3 marks / 3 markah]
                                                                          Answer / Jawapan:
                                                                                         9 000
                 (b)  Evaluate and give your answers in standard          9 000 seconds =   3 600   = 2.5 h
                    form.                                2.2.2
                    Nilaikan dan beri jawapan anda dalam bentuk piawai.     Distance = Speed × Time
                                                                                           –1
                                                                                  = 75 kmh  × 2.5
                            5.43
                    (i)                    [2 marks / 2 markah]                   = 187.5 km
                         30.1 – 0.54
                                                                                  = 187 500 m
                    (ii)  (6.09 × 10 ) ÷ (2.31 × 10 )                             = 1.875 × 10  m
                                 2
                                               –3
                                                                                             5
                                           [2 marks / 2 markah]
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