Page 9 - TOP ONE MATHS F3
P. 9
Top One (MATHS F3) Penerbitan Pelangi Sdn Bhd
Mathematics Form 3 Chapter 2 Standard Form
(b) The diagram below shows a wooden block in Answer / Jawapan:
the shape of cylinder. 2.2.3 Density = Mass
Rajah di bawah menunjukkan sebuah blok kayu Volume
berbentuk silinder. Mass
0.9 kgm =
–3
14 cm 7.7 × 10 –3
–3
Mass = (0.9 × 7.7 × 10 ) kg
–3
= 6.93 × 10 kg
= 0.00693 kg
50 cm
(c) The table below shows the price of some fruits.
Jadual di bawah menunjukkan harga bagi beberapa
buah-buahan. 2.2.3
3
(i) Calculate the volume, in m , of the wooden
block. State your answer in standard form. Fruits Price
Hitung isipadu, dalam m , blok kayu itu. Nyatakan Buah-buahan Harga
3
jawapan anda dalam bentuk piawai. Mango / Mangga RM5.99 / kg
Use / Guna: π = 22 [2 marks / 2 markah] Mangosteen / Manggis RM9.90 / kg
7
Answer / Jawapan: Puan Rosmah bough 3.5 kg of mango and 1 kg
Volume of cylinder = πr h of mangosteen. Calculate the total price that
2
22 she needs to pay. State your answer in three
= × (0.07) × 0.5
2
7 significant figures.
= 7.7 × 10 m 3 Puan Rosmah membeli 3.5 kg mangga dan 1 kg
–3
manggis. Hitung jumlah harga yang perlu dibayarnya.
Nyatakan jawapan anda dalam 3 angka bererti.
(ii) Given the density of the wooden block [3 marks / 3 markah]
–3
is 0.9 kgm . Find the mass, in kg, of the Answer / Jawapan:
block in single number.
Diberi ketumpatan blok kayu tersebut ialah Total price
–3
0.9 kgm . Cari jisim, dalam kg, blok kayu tersebut = RM5.99(3.5) + RM9.90
dalam nombor tunggal. = RM30.865
[2 marks / 2 markah] = RM30.90
HOTS Challenge
Write 3.45 × 10 seconds as nanoseconds.
–7
Tulis 3.45 × 10 saat sebagai nanosaat.
–7
3.45 × 10 –7
= 3.45 × 10 × 10 9
–7
= 3.45 × 10 2
= 345 nanoseconds
HOTS
Extra
15 © Penerbitan Pelangi Sdn. Bhd.
02 TOP MATH F3.indd 15 03/01/2020 8:00 AM

