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 Mathematics  Form 3  Chapter 2  Standard Form     Mathematics  Form 3  Chapter 2  Standard Form
 (c)  640 × 110 ÷ 1 800  PT3 Standard Practice  2  Section C  (b)  (i)  Volume of cylinder = πr h
                                                                                          2
    = 70 400 ÷ 1 800                                                =  22  × (0.07)  × 0.5
                                                                                 2
    = 7.04 × 10  ÷ (1.8 × 10 )  Section A    1.  (a)  k = 7, l = – 6   7
 3
 4
                                                                              –3
    = 3.91 × 10 4 – 3    1.  6.47 × 10  = 0.000647          ∴ k × l = 7 × (–6) = –42  = 7.7 × 10  m 3
 –4
    = 3.91 × 10       5.43       5.43                                           Mass
 Answer: A  (b)  (i)           =                               (ii)   Density =   Volume
                                 29.56
 (d)  2.63 × 10  × 3.2 × 10 –2  30.1 – 0.54  = 1.84 × 10 –1                 –3    Mass
 4
    = 2.63 × 3.2 × 10 4 + (–2)    2.   3.43 × 10 –3  =   3.43 × 10 –3           0.9 kgm  =   7.7 × 10 –3
                                          –3
                            2
    = 8.42 × 10 2  700 000  7 × 10 5     (ii)  (6.09 × 10 ) ÷ (2.31 × 10 )             mass = (0.9 × 7.7 × 10 ) kg
                                                                                             –3
         = 0.49 × 10 –3 – 5  = 6.09 ÷ 2.31 × 10 2 – (–3)                                –3
 (e)  1.5 × 10  × 5.1 × 10  ÷ (4 × 10 )          = 4.9 × 10 –9  = 2.64 × 10 5  = 6.93 × 10  kg
 2
 –2
 3
    = (1.5 × 5.1 ÷ 4) × 10 –2 + 3 – 2  Answer: C  3                           = 0.00693 kg
    = 1.91 × 10      (c)  (i)  2 356 = 2.36 × 10  m        (c)  Total price
 –1
                                     9
              (ii)  1.05 × 10  = k × 10                         = RM5.99(3.5) + RM9.90
                           11
   3.  2k – 3s                                                  = RM30.865
                                        2
  11.  (a)  (i)             k = 1.05 × 10  billion
 = 2(6.14 × 10 ) – 3(1.09 × 10 )                                = RM30.90
 3
 4
 China   Africa   = 1.228 × 10  – 3.27 × 10 4
 4
 Cina  Afrika  = –2.042 × 10 4    2.  (a)  9 000 seconds =   9 000   = 2.5 h
                              3 600                           HOTS Challenge
 Population  9  8  Answer: C     Distance = Speed × Time
 Jumlah Penduduk  1.32 × 10  8.32 × 10  = 75 kmh  × 2.5
                               –1
   4.  Answer: D                                       3.45 × 10 –7
 Land area (km )  6  7         = 187.5 km              = 3.45 × 10  × 10 9
 2
                                                                  –7
 Luas tanah (km )  9.60 × 10  2.66 × 10         = 187 500 m
 2
   5.  A  3.0862 = 3.09 (3 s.f.)         = 1.875 × 10  m  = 3.45 × 10 2
                                  5
 B  3.0785 = 3.08 (3 s.f.)                             = 345 nanoseconds
    (ii)  Number of people per km in China
 2
 = 1.32 × 10  ÷ 9.60 × 10 6  C  3.0713 = 3.07 (3 s.f.)
 9
 = 0.1375 × 10 3  D  3.8045 = 3.80 (3 s.f.)
 = 1.375 × 10 2  Answer: B
 2
 Number of people per km in Africa
 = 8.32 × 10  ÷ 2.66 × 10 7  Section B
 8
 = 3.13 × 10
   1.  (a)   Number of
 significant
 Number  Answer
 Nombor  figures  Jawapan
 Bilangan
 angka bererti
 (i)  0.0183  2  0.018
 (ii)  299 530  3  300 000
 (iii) 43  4  43.00
 (b)  0.000045 = 4.5 × 10 –5
    +1

   2.  (a)  299 530  300 000
 (b)  0.000000085 ÷ 1.7 × 10
 –9
    =   8.5 × 10 –8  ÷ 1.7 × 10 –9
    = 8.5 ÷ 1.7 × 10 –8 +   9
    =   50
 7  © Penerbitan Pelangi Sdn. Bhd.  © Penerbitan Pelangi Sdn. Bhd.  8

 A5



 BOOKLET ANS MATH F3.indd   5                                                             03/01/2020   10:20 AM
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