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Mathematics Form 3 Chapter 4 Scale Drawings Mathematics Form 3 Chapter 4 Scale Drawings
30 1 height of painting 1 Section C
(c) = PT3 Standard Practice 4 6. =
height of building 600 (1.1 × 100) 20 2 2
height of building = 30 × 600 height of painting = (1.1 100) ÷ 20 1. (a) (i) Length of LM = 15 – 12
= 18 000 cm Section A = 5.5 cm = 9 cm
= 18 000 ÷ 100 m 1. 2 cm : 1 m = (2 cm : 100 cm) ÷ 2 Answer: B Length of drawing = 1
= 180 m = 1 : 50 9 1
3
Section B Length of drawing = 9 × 3
Answer: A
10. (a) (i) Dimension: = 27 cm
Actual length = 2.5 + 1.5 + 4 = 8 m 1. Object Scale drawing Scale
Actual width = 6 m 8 1 Objek Lukisan berskala Skala 1
2. = (ii) Length of KL in drawing =
Actual height 7 500 (a) 12 1
(ii) Area of the living room = 4 × 3 Actual height = (8 × 7 500) cm 3
= 12 m 2 = 60 000 cm 18 cm 1 : 3 Length of KL in drawing = 12 × 3
= 600 m 6 cm = 36 cm
(iii) Area of bedroom 1 Answer: B (b) Area of KLM in drawing
= (3 × 4) – (1 × 0.5) 1
= 11.5 m 5 cm = × 27 × 36
2
2
3. Answer: B 10 cm 1 = 486 cm 2
Total cost of carpet 1 : 2
= 11.5 × RM60
= RM690 4. Radius of the swimming pool (b) (i) 1 cm
= (5 – 0.75 – 0.75) ÷ 2 (c) 1 cm
(iv) Height of bathroom 1 = 1.75 cm
= 2 ÷ (1 × 0.5) 1.75 1 7 m 2 7 m 2 1 : 1
= 4 m Actual radius = 400
Actual radius = 1.75 × 400 (d)
= 700 cm
= 7 m 3 m 15 cm 1 : 20 (ii)

Area of the swimming pool = pr 2 2 cm
22
= × (7) 2 2 cm
7
= 154 m 2 2. (a)
The scale drawing is bigger
Answer: D
than the object.
Lukisan berskala adalah lebih
besar daripada objek.
5. Length of KL in drawing
1 1 : 3
135 = × 15 × KL The scale drawing is the
2
135 × 2 same as the object.
KL = Lukisan berskala adalah sama 0.6825 1
15 1 saiz dengan objek. (c) Actual height = 600 000
= 18 cm 1 : 2
Actual height = 0.6825 × 600 000
Actual length of KL The scale drawing is = 409 500 cm
= (18 × 10 000) cm smaller than the object. = 4.095 km
= 180 000 cm Lukisan berskala adalah lebih
= 1.8 km kecil daripada objek.
Answer: C
(b) 5 cm : 1 m = (5 cm : 100 cm) ÷ 5
= 1 : 20

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BOOKLET ANS MATH F3.indd 10 03/01/2020 10:20 AM