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Mathematics Form 3 Chapter 4 Scale Drawings Mathematics Form 3 Chapter 5 Trigonometric Ratio
4. (a) (i) Scale CHAPTER
= area of drawing : Actual area HOTS Challenge 5 Trigonometric Ratios
= 400 : 25 Nisbah Trigonometri
= 20 : 5 Length of bedroom 1 in the plan
= 1 : 1 = (16 – 5 – 2(2.5))
4 = 6 cm
1. (a) (i) adjacent side / sisi bersebelahan 6. (a) True
(ii) New scale Width of bedroom 1 in the plan (b) False
= Length of drawing : actual length = 3 + 3 (ii) opposite side/ sisi bertentangan
= 2 : 4 = 6 cm (iii) hypotenuse / hipotenus (c) False
(d) False
= 1 : 2
6 1 (b) (i) opposite = BC (e) True
= adjacent AB
(b) length of square = 324 Actual length 50
= 18 cm Actual length = 6 × 50 cm (ii) opposite = BC 7. (a) sin 30° = PQ
= 300 cm hypotenuse AC PR
length of drawing 1
= = 3 m adjacent AB PQ
actual length 4 (iii) hypotenuse = AC PR = 0.50
18 1 Actual width = 3 m
= PQ
actual length 4 10 = 0.50
actual length = 4 × 18 Area of bedroom 1 = 3 × 3 2. (a) 5 PQ = 0.50 × 10
= 9 m
2
= 72 cm tan θ 13 = 5 cm
Height of drawing 40 5
(c) (i) = sin θ AB
actual length 2.8 × 1 000 12 8. (a) cos x =
1 BC
=
70 cos θ 12 = 12
Scale = 1 : 70 13 13
AB : BC = 12 : 13
= 24 : BC
42 1 6 3
(ii) = 3. (a) sin θ = O = = BC = 13 × 2
length of white board 70 H 10 5
length of white board = 42 × 70 A 8 4 = 26 cm
2
= 2 940 mm (b) cos θ = H = 10 = 5 AC = 26 – 24 2
= 294 cm O 6 3 = 10 cm
(a) tan θ = = =
Length of white board : width of A 8 4 3
white board (b) sin x = 4
= 3 : 2 9 3
= 294 : 196 4. (a) cos 29° = 0.8746 AC = 4
(b) tan 80° = 5.671
Width of white board = 196 cm (c) sin 50° = 0.7660 = 9 × 4
3
Total length of red ribbon needed = 12 cm
= (294 × 2) + (196 × 2)
–1
= 980 cm 5. (a) θ = cos 0.55
= 56.63° (c) Let MB be a line perpendicular to BC
2
2
–1
(b) θ = tan 0.15 AM = 10 – 8 = 6 cm
= 8.53° MB
tan z =
(c) θ = sin 0.87 AM
–1
= 60.46° = 8
6
4
=
3
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BOOKLET ANS MATH F3.indd 11 03/01/2020 10:20 AM
