Page 45 - Hybrid PBD 2022 Tg 4 - Matematik

Matematik Tingkatan 4 Bab 5 Rangkaian dalam Teori Graf

Jawapan / Answer :
(a) RM50
A D RM60 E

RM55 RM90
B C RM80
RM40 RM85
RM30 RM110 F
RM20
G
H

(b) A → D → E → F → H
Penerbitan Pelangi Sdn Bhd. All Rights Reserved
= RM50 + RM60 + RM80 + RM20
= RM210
A → B → C → H
= RM55 + RM85 + RM110
= RM250
A → G → B → C → H
= RM40 + RM30 + RM85 + RM110
= RM265
A → D → C → H
= RM50 + RM90 + RM110
= RM250
Perjalanan yang paling murah ialah A → D → E → F → H yang berharga RM210.
The cheapest route is A → D → E → F → H which costs RM210.

(c) Harga baru bagi laluan A → D → E → F → H / New price for the route A → D → E → F → H
= RM50 + RM60 + (1.5 × RM80) + (1.5 × RM20)
= RM260

Harga baru bagi laluan A → D → E → F → H ialah RM260. Zul tidak boleh memilih
perjalanan bas yang sama kerana perjalanan bas mengikut laluan A → B → C →
H dan A → D → C → H adalah lebih murah iaitu RM250.
The new price for route A → D → E → F → H is RM260. Zul cannot choose the same bus trip route
because the bus trip along the A → B → C → H and A → D → C → H routes are cheaper at RM250.

Kuiz 5

75 © Penerbitan Pelangi Sdn. Bhd.

05 Hybrid PBD Mate Tg4.indd 75 22/10/2021 5:49 PM