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Mathematics  Form 5  Chapter 2  Matrices
            19.  Find the products of matrices, FG and GF. Hence, determine whether matrix G is an identity matrix.  PL 2
               Cari hasil darab matriks, FG dan GF. Seterusnya, tentukan sama ada matriks G ialah matriks identiti.
                  Example                                                –4 3      1 0
                                                                 (a)  F =     , G =   
                     5 –1                                            1 2       0 1
                               1 0
                F =   7 9  , G =   1 1
                                                                           
                                                                     –4 3 1 0   =   –4 3 
                                                                                  1 2
                 5 –1 1 0   =   16 9     If AB = BA = A, then B is         –4 3 
                                                                      1 2 0 1
                       
                              4 –1
                 7 9 1 1
                                                                     1 0 –4 3
                              5 –1
                 1 0 5 –1
                                                                     0 1 1 2
                         12 8        an identity matrix.        FG = GF = F  =   1 2
                                           Jika AB = BA = A, maka B
                            =
                 1 1 7 9
                                           ialah matriks identiti.
                FG  GF  F                                         Hence, G is an identity matrix.
                Hence, G is not an identity matrix.                 Maka, G ialah matriks identiti.
                Maka, G bukan matriks identiti.
                          2 4 5                                      8 –3 –1   
                                      0 0 1
                                                                                       1 0 0
                (b)  F =   –5 1 7  , G =   0 1 0                 (c)  F =   2 0 –6  , G =   0 1 0
                         3 6 –1       1 0 0                              1 4   5       0 0 1
                     2 4 5 0 0 1       5 4 2                         8 –3 –1 1 0 0      8 –3 –1
                                                                                    
                     –5 1 7 0 1 0    =   7 1 –5                      2 0 –6 0 1 0    =   2 0 –6
                     3 6 –1 1 0 0      –1 6 3                        1 4   5 0 0 1      1 4   5
                                   3 6 –1                                    8 –3 –1 
                                                                     1 0 0 8 –3 –1
                     0 0 1 2 4 5
                     0 1 0 –5 1 7    =   –5 1 7                      0 1 0 2 0 –6    =   2 0 –6
                     1 0 0 3 6 –1      2 4 5                         0 0 1 1 4    5     1 4   5
                    FG  GF  F                                     FG = GF = F
                    Hence, G is not an identity matrix.             Hence, G is an identity matrix.
                    Maka, G bukan matriks identiti.                 Maka, G ialah matriks identiti.


                                            2 9
                              5 1          
            20.  Given that K =   2 –3   and L =   6 4  , solve each of the following.  PL 3
                                     2 9
                         5 1       
               Diberi K =   2 –3   dan L =   6 4  , selesaikan setiap yang berikut.

                  Example                                        (a)  (K + L)I
                KI – IL                                               5 1     2 9 1 0
                                                                     2 –3    
                                                                            +
                                                                              6 4 0 1
                         
                 5 1 1 0   –   1 0 2 9                                7 10 1 0
                                                                             
                             0 1 6 4
                 2 –3 0 1
                   5 1                                          =  8 1 0 1
                           2 9
                =   2 –3   –   6 4                                     7 10
                    3 –8                                          =   8 1 
                =   –4 –7
                (b)  2IL + I                                     (c)  (IK)L
                          2
                                                                                2 9
                                                                      1 0 5 1
                                 1 0 1 0
                      1 0 2 9
                    2                                              
                               +
                                                                      0 1 2 –3 6 4
                                 0 1 0 1
                      0 1 6 4
                                                                            
                                                                =   5 1 2 9
                        2 9
                               1 0
                    = 2  6 4   +   0 1                                 2 –3 6 4
                        5 18                                      =    16 49 
                    =  12 9                                            –14 6
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