Page 13 - Top Class F5 - Mathematics (Chapter 2)

Mathematics Form 5 Chapter 2 Matrices

11. Given that P =  3 4  and Q =  –1 6  , solve each of the following. PL 3
2 –9
5 7
 3 4   –1 6 
Diberi P = 2 –9 dan Q = 5 7 , selesaikan setiap yang berikut.
Example (a) 3(P – Q)
2(P + Q) 3 4 –1 6 4 –2
= 3
–
= 2
+
2  3 4   –1 6   2 10  3  2 –9   5 7   –3 –16 
2 –9
5 7
7 –2
12 –6
 4 20  =  
= 14 –4 –9 –48
(b) 2P + 2Q (c) 3P – 3Q
+ 2
=
– 3
=
–
+
2  3 4   –1 6   6 8   –2 12  3  3 4   –1 6   9 12   –3 18 
2 –9 5 7 4 –18 10 14 2 –9 5 7 6 –27 15 21
4 20
=  14 –4  =  12 –6 
–9 –48
Conclusion / Kesimpulan:
n(P + Q) = nP + nQ n(P – Q) = nP – nQ

12. Solve each of the following. PL 3
Selesaikan setiap yang berikut.

Example 1 –8 7 3 4 (b) 8[2 –1] + 3[–9 1]
– 5
(a)     = [16 –8] + [–27 3]
–2 1

2  7 –1  + 1 10 –5  2 12 18 15 20 = [–11 –5]
5 25 40
3 –6
–4 3.5
–
 14 –2   2 –1  =  6 9   –10 5 
= 6 –12 + 5 8 –19 –16.5
 16 –3  =  16 4 
= 11 –4

   2 –3  (d)       2 9 3 
   
3
–1
–8
1
3
5
1
– 2
+ 9
1
(c) 3 –6 2 + 4 8 –20 17 –2 6 (e) 4 –1 – 1 – –27
3 –9 4 –32 3 =       5 8 –7 9 1 12
27
–2
–8
–
+
1
     
12
–18
17
–
 15 3    =   = –4 – 1 – –9
4
2
21
= –18 6 + 2 –5 –13 20 –7 4
9 –27 1 –8 –2
 
  = 4
1
1
2
15
4
2
= –16 1 23
10 –35
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