Page 10 - Praktis Hebat 2021 - Additional Mathematics F4
P. 10

Additional Mathematics  Form 4  Answers
                                          ANSWERS






                                                                                  f(x)
                 PRACTICE  Functions                                             16
                  1     Fungsi                                                   14
                                                                                 12
                                                                                 10
               PAPER 1
                                                                                 8
               1.  (a)  The relation is a function because each object           6
                    has only one image.                                          4
                    Hubungan ini ialah fungsi kerana setiap objek                2
                    mempunyai satu imej sahaja.                                                 x
               2.  (a)  Vertical line test                                –2  –1  0   1   2   3
                    Ujian garis mencancang                                   4               1
                (b)  This graph is not a function because when tested    13.  (a)  x = 1, x = – —  (b)  x = 1, x = —
                                                                                             5
                                                                             3
                    with the vertical line test, the line cuts two points
                                                                           3
                                                                                               2
                    on the graph.                            14.  (a)  x = 1, x = —  (b)  x = –1, x = – —
                    Graf ini bukan fungsi kerana apabila diuji dengan      5                   3
                    ujian garis mencancang, garis itu memotong dua
                    titik pada graf.                         15.  (a)  (i)   h(3)= 120   (ii)  h(6)= 96
               3.  f : x → x 3                                  (b)  (t = 0, t = 8)
               4.  (a)  Domain = {a, b, c, d}                16.  (a)  fg(x) = 8x – 5   (b)  gf(x) = 8x – 13
                    Codomain / Kodomain = {1, 2, 5, 7, 8}    17.  (a)  f (x) = 16x + 5   (b)  g (x) = 4x – 21
                                                                    2
                                                                                      2
                    Range / Julat = {1, 5, 7, 8}            18.   p = 5, q = –1
                (b)  Domain = {–1, 0, 1, 2}                            1
                    Codomain / Kodomain = {0, 1, 2, 3, 4, 5}   19.  (a)  x = —    (b)  x = 32
                                                                       2
                                                                   1
                    Range / Julat = {0,1,2,3,4}              20.  x = —
               5.  (a)  f(3) = 9                                   4
                (b)  f(–1) = –7                              21.  (a)  g(x) = 5x   (b)  g(x) = x 2
                             3
                (c)  x = 3, x = – —                          22.  (a)  9x – 2     (b)  x – 1
                                                                                      2
                             2
                                                             23.  (a)  g(x) = 4 – x   (b)  g(–3) = 7
               6.  (a)  f(2) = –7   (b)  f(–8) = 5
                                                                       7
               7.  (a)  x = 3     (b)  x = 3, x = –2            (c)  x = —
                                                                       6
               8.  (a)  f(–1) = –11   (b)  x = –8                       1               1
               9.  (a)  p = 3     (b)  x = –1                24.  (a)  f(x) = —x + 1   (b)  x = —
                                                                        2
                                                                                        3
                                               9
              10.  (a)  f(–1) = –6   (b)  x = 0, x = – —     25.  (m = 5, n = 2)
                                               4
              11.  (a)  0 < f(x) < 6   (b)  0 < f(x) < 13    26.  (a)  p = –2     (b)  q = 4, q = –4
              12.  (a)  f : x → |2x – 3|, –3 < x < 3         27.  p = 3, q = –1
                                                                         5
                                                                                            2
                      x     –3    0    1.5   3               28.  (a)  g(x) = —x  + 1   (b)  g(x) =   5x  + 30x + 41
                                                                           2
                                                                         2                     4
                      f(x)  9     3    0     3                                                 7
                                                             29.  (a)  g(x) = 2x + 1   (b)  x = 3, x = –
                                  f(x)                       30.  (a)  f (2) = 1   (b)  f (5) = 2  11
                                                                    –1
                                                                                      –1
                                10                              (c)  f (10) = 3
                                                                    –1
                                 9
                                 8                           31.  (a)  f is a function because the type of function for the
                                 7                                  arrow diagram above is a one - to - one function.
                                 6                                  Each element in the domain is mapped to only
                                 5                                  one element in the codomain. Therefore, the
                                 4                                  function f has an inverse function.
                                 3                                  f ialah suatu fungsi kerana jenis fungsi bagi
                                 2                                  gambar rajah anak panah di atas ialah fungsi
                                 1                                  satu dengan satu. Setiap unsur dalam domain
                                                x                   dipetakan kepada hanya satu unsur dalam
                      –3  –2  –1  0   1   2  3
                                                                    kodomain. Oleh itu, fungsi f mempunyai fungsi
                (b)  f : x → |5x – 5|, –2 < x < 3                   songsang.
                                                                (b)  f is not a one - to - one function because two
                      x     -2    0    1     3
                                                                    different objects have the same image. Therefore,
                      f(x)  15    5    0     10                     the function f has no inverse function.
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     ANS HEBAT ADD MATH F4 1P.indd   1                                                             09/04/2021   3:49 PM
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