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3.  y = x ln x – x                               6.  (a)  f'(x) = 10ax  – 5x –6
                                                                                    4
                          2
                      dy  = x + 2x ln x – 1                               By comparison,
                      dx                                                    10a = 5
                                                                                 1
                         2       1    2                2  1  1                a =
                        x ln x dx  =   2x ln x + x – 1 dx –   x –  dx            2
                       0         2  0       2        0  2 2  2             –25b = –5
                                                    1
                                           4 3
                               =  1 3 x ln x – x  –   1 x  –  x 4             b =  1
                                    2
                                                  2
                                 2          0  4    2  0                         5                           [3]
                                                       1
                                                          4
                               =  1 [(2) ln 2 – 2] –  3 1 (2)  –  (2)
                                                    2
                                      2
                                                                                  4
                                 2              4      2               (b)  f'(x) = 5x  – 5x
                                                                                      –6
                               = ln 4 – 1                                 When f'(x) = 0,
                                                                              4
                                                                                   –6
                                                            [5]             5x  = 5x
                                                                             x
                                                                              4
                                     2
                    4.   dy   =  2x(2 – x) – x (–1)                          x –6  = 1
                      dx       (2 – x) 2                                     x  = 1
                                                                              10
                                 2
                         =  4x – 2x  + x 2                                    x = ±1
                            4 – 4x + x 2
                           –x  + 4x                                       When x = 1,
                             2
                         =
                           (x – 2) 2                                      y = 1  +   1
                                                                              5
                         =  x(4 – x)                                        = 2  1 5
                           (2 – x) 2
                         3                3                               When x = –1,
                         x(4 – x)   dx =  3  x 2  4
                         (2 – x) 2   2 – x                                y = (–1)  +   1
                                                                                 5
                       0                  0                                         (–1) 5
                                  =  9   – 0                                = –2
                                    2 – 3                                 The turning points are (1, 2) and (–1, –2).
                                  = –9                                                                       [4]
                                                            [4]      7.  (a)  When x = a,  dy  = 0.
                    5.   dy   =   4x  + 4 dx                               3         dx
                              3
                      dx                                                  a  – 8  = 0
                                                                           2a
                                                                             2
                           4x
                             4
                               + 4x + c
                         = 5 Penerbitan Pelangi Sdn Bhd. All Rights Reserved.
                                                                              a  = 8
                                                                               3
                            4
                      dy  = 3 when x = –1.                                    a = 2
                      dx                                                   d y  6x  – 4x(x  – 8)             [2]
                                                                                  4
                                                                                        3
                                                                            2
                      (–1)  + 4(–1) + c = 3                            (b)   dx 2  =   (2x )
                         4
                                                                                      2 2
                              –3 + c = 3                                      =  6x  – 4x  + 32x
                                                                                      4
                                                                                  4
                                  c = 6                                              4x 4
                      dy  = x  + 4x + 6                                       =  2x  + 32x
                                                                                  4
                           4
                      dx                                                          4x 4
                        y  =   x  + 4x + 6 dx                             When x = 2,
                             4
                                                                           d y
                                                                                   4
                                                                            2
                            5
                                 2
                         =  x    +  4x    + 6x + d                        dx 2  =  2(2)  + 32(2)
                                                                                   4(2)
                                                                                      4
                           5    2                                               3
                                    1
                      When x = –1, y =  .                                     =  2
                                    2                                       3   . 0
                      (–1) 5  + 2(–1)  + 6(–1) + d =  1                     2
                                 2
                        5                     2                           (2, 3) is minimum point.
                                          d =  47                                                            [4]
                                             10                        (c)  y =     x  – 8  dx
                                                                                3
                         x
                      y =   + 2x  + 6x +  47                                    2x 2
                               2
                         5           10                                        x 3   8
                      When x = 3,                                           =    2x 2  –  2x 2  dx
                                                                               x
                      y =  3 5  + 2(3)  + 6(3) +  47                        =     –   4   dx
                                 2
                          5              10                                    2   x 2
                        = 89.3                                              =  x 2  +   + c
                                                                                  4
                                                            [6]               4   x
                         Cambridge IGCSE
                                          TM
                  206     Ace Your Additional Mathematics
         Answers Add Math.indd   206                                                                             14/03/2022   12:29 PM
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