Page 65 - Hybrid PBD 2021 Form 1 - Matematik
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Matematik  Tingkatan 1  Bab 3
                20.  Cari nilai bagi setiap yang berikut tanpa menggunakan kalkulator.   SP 3.2.4      TP2
                  Find the value of each of the following without using a calculator.
                                                    (a)  9                          (b)  (–0.4)
                                                         3
                                                                                             3
                       (–2)                            = 9 × 9 × 9                      = (–0.4) × (–0.4) × (–0.4)
                          3
                       = (–2) × (–2) × (–2)            = 729                            = –0.064
                       = –8
                                                                                                7
                   (c)  0.8 3                             4  3                            1  3      3
                                                                                         2
                                                        –
                                                          5
                                                                                          3
                       = 0.8 × 0.8 × 0.8            (d)                           (e)    =   3
                                                                                                          7
                                                                                                     7
                                                                                                7
                                                                
                       = 0.512                         = –  4  ×  –  4  ×  –  4              =         
                                                                                                  ×
                                                                                                       ×
                                                                  5
                                                                                                          3
                                                                                                3
                                                                                                     3
                                                                        5
                                                           5
                                                           64                                  343      19
                                                       = –                                   =      = 12
                                                           125                                  27      27
                21.  Cari nilai bagi setiap yang berikut dengan menggunakan kalkulator.   SP 3.2.4      TP2
                  Find the value of each of the following using a calculator.
                                                                           3
                                           (a)  9.8                (b)  (–14)
                                                 3
                             3
                       (–12.1)                 = 941.192               = –2 744                    Tip Penting
                       = –1 771.561                                                               =   a   ×   a   ×   a     
                                                                                               a 3
                                                                                                       b
                                                                                                    b
                                                                                               b
                                                                                                           b
                                                                                                  =  a × a × a    
                                                                                               a 3
                   (c)  0.4                (d)    3              (e)    3                  b      b
                                               1
                          3
                                                                         1
                       = 0.064                 5                       8  5                       =   a        
                                                                                               a 3
                                                  1                         46                 b    b × b × b
                                               =                       = 551
                                                 125                        125
                22.  Cari punca kuasa tiga bagi setiap yang berikut dengan menggunakan kaedah pembahagian berulang
                  dengan pemfaktoran perdana.    SP 3.2.5      TP2
                  Find the cube root of each of the following by repeated division by prime factorisation method.
                                                                                         9 261
                                                      2 197
                                                 (a)                           (b)                7   9 261
                                                                                       3
                                                     3
                     343
                   3                                                                                   7   1 323
                                                            13 × 13 × 13
                                                                                     9 261
                                                   2 197
                                                          3
                                                 3  =  13 2 197       3                  7    189
                     343
                             7 × 7 × 7
                      =                         = 13                       =         3       27
                   3       3           7 343                            13     169
                                                                                       7 × 7 × 7 × 3 × 3 × 3
                                                                                     3
                         = 7           7    49                          13       13                       3          9
                                                                                       21 × 21 × 21
                                                                                     3
                                       7      7                                     1  =         3          3
                                              1                                    = 21                              1
                                                                                         1 000
                   (c)                      (d)                            (e)  
                                                      729
                        15 625
                                                                                       3
                                                     3
                       3
                             5 15 625                         3 729                            5   1 000
                             5    3 125                       3 243                            5    200
                             5       625                      3    81                          5     40
                             5       125                      3    27                          2        8
                             5         25                     3       9                        2          4
                             5           5                    3       3                        2          2
                                         1                             1                                  1
                                                                                              5 × 5 × 5 × 2 × 2 × 2
                                                                                     1 000
                                                          3 × 3 × 3 × 3 × 3 × 3
                                                   729
                     15 625
                   3                        3  =              3  = 
                                                                                            3
                                                        3
                       5 × 5 × 5 × 5 × 5 × 5
                                                                                              5 × 2 × 5 × 2 × 5 × 2
                   =                      =                              = 
                                                          9 × 9 × 9
                     3
                                                        3
                                                                                            3
                   =                          = 9                                 = 
                       25 × 25 × 25
                     3
                                                                                              10 × 10 × 10
                                                                                            3
                   = 25
                                                                                           = 10
              © Penerbitan Pelangi Sdn. Bhd.                    38
         03 Hybrid PBD Mate Tg1.indd   38                                                                         03/09/2021   3:33 PM
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