Page 17 - Pra U STPM 2022 Penggal 2 - Mathematics
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Mathematics Semester 2  STPM  Chapter 1 Limits and Continuity
                  7.  The function f is defined by

                                    3 – 2e ,   x , 0
                                         x
                            f(x) =    2,    x = 0                                                             1
                                    3e  – 2,   x . 0
                                     x
                     (a)  Determine the existence of limit f(x) as x approaches 0.
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                     (b)  State, with a reason whether f(x) is continuous at x = 0. Hence, determine the intervals on which f
                         is continuous.

                  8.  The function f is defined by
                                    f(x) =    ln x,  0 , x , 1,
                                             2
                                           ax  + b,  1 < x , ∞.
                     Given f(2) = 3, determine the values of a and b for which f is continuous on (–∞, ∞).

                  9.  The function f is defined by
                                             2
                                            x  – 9  ,  x ≠ 3
                                    f(x) =  |x – 3|
                                            6,      x = 3
                     Determine whether f is continuous at x = 3.

                 10.  Evaluate
                                                                             x – 5
                                4h
                                                                      lim
                           lim
                     (a)   h → 0  e  – 1                        (b)  h → –∞     7
                                2h
                                                                               2
                                                                             4x  +
                               e  – 1
                 11.  A function f is defined by
                                               f(x) = ln (x + 2), –2 , x , ∞.
                     (a)  Show that f is continuous on its domain.
                     (b)  Sketch the graph of f.
                 12.  Use the intermediate value theorem to show that there exists a solution to the equation cos x = x in the
                     interval [0,   π ].
                               2
                 13.  Evaluate
                                  2
                                                                              2
                                3x  + 16
                                                                           16x  +
                           lim
                                                                      lim
                     (a)   x → 0    – 4                       (b)  x → ∞     1
                                    x
                                     2
                                                                            2x – 1
                 14.  Show that the graph of y = x  – 4x + 1 intersects the x-axis in the interval [0, 2]. Can the same be said
                                             2
                     for the graph of y =   2x – 3  ?
                                       x – 1
                 15.  The function f is defined by
                                            2
                                    f(x) =   x  + 2x + 8,  x , 0
                                             x
                                           2e  + c,    x > 0
                               lim
                                            lim
                     (a)  Find   x → 0 – f(x) and   x → 0 + f(x). Hence, determine the value of  c such that function f is continuous
                         at x = 0.
                     (b)  Describe the continuity of the function f for
                         (i)  x = 0                      (ii)  x , 0             (iii)  x . 0
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         01 STPM Math(T) T2.indd   15                                                                  28/01/2022   5:30 PM
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