Page 27 - Pra U STPM 2022 Penggal 2 - Mathematics
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Mathematics Semester 2  STPM  Chapter 4 Differential Equations

                                                                                                          1
                                                                                                      –∫
                                                                                                        dx
                                      Multiplying both sides of the differential equation with the integrating factor is e     x .
                                       dy    e  – —dx 2  –   1    e  – —dx 2	 y  = –2x  e  – —dx 2
                                                         1
                                              1
                                                                       1
                                          1
                                                                    1
                                                        ∫    x
                                                                      ∫    x
                                            ∫    x
                                       dx          x 1
                                                    d    ye  – —dx 2   = –2xe  – —dx
                                                           1
                                                                      1
                                                      1
                                                         ∫    x
                                                                     ∫    x
                                                   dx
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                                                                        1
                                                           1
                                                      1
                                                                      ∫    x
                                                         ∫    x
                                                                =  –2xe
                                                    \  ye  – —dx 2 ∫  – —dx   dx
                                                                 ∫
                                                            –1
                                                                       –1
                                                       \ y(x )  =  – 2x(x  ) dx
                                                                 ∫
                                                           yx   =  –2 dx
                                                            –1
                                                            –1
                                                           yx   = –2x + A
                                                          \ y  = –2x  + Ax
                                                                   2
                     Example 9
                                                              dy
                  Find the general solution to the differential equation    = x – 2y.
                                                              dx
                                       dy
                  Solution:               = x – 2y
                                       dx
                                                                            dy
                                      Arrange the differential equation to the form   dx   + f(x)y = g(x).
                                       dy
                                          + 2y = x
                                       dx
                                      \ f(x) = 2 and g(x) = x.
                                                                                                              4
                                      So the integrating factor is e  ∫  2 dx  = e .
                                                                    2x
                                      Multiplying both sides of the equation with e ;
                                                                           2x
                                       dy  (e ) + 2(e )y  = x(e )
                                                  2x
                                                          2x
                                           2x
                                       dx
                                           \   d   (ye )  = xe 2x
                                                   2x
                                              dx
                                                        ∫
                                                           2x
                                                \ ye   =     xe  dx + C
                                                    2x
                                      Integrating the right side by parts:
                                       du   = e  and v = x
                                             2x
                                       dx
                                            ∫
                                               2x
                                      \ u =     e  dx =   1  e  and   dv   = 1
                                                        2x
                                                      2
                                                              dx
                                                        1
                                                     ∫
                                      \ ye  =   1  xe  –     e  dx + C
                                          2x
                                                          2x
                                                  2x
                                              2         2
                                      \ ye  =   1  xe  –   1 e  + C
                                                  2x
                                          2x
                                                        2x
                                              2       4
                                         \ y =   1 x –   1  + Ce –2x
                                              2     4
                                                                                                       135
         04 STPM Math(T) T2.indd   135                                                                 28/01/2022   5:44 PM
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