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Mathematics Semester 2  STPM  Chapter 4 Differential Equations
                                                                                           dy
                                                                                                 2
                                                                                                      2
                6.  Using the substitution y = vx, find the general solution of the differential equation 2xy    = y  – 4x .
                                                                                           dx
                   Show that the particular solution which satisfies the condition  y =  a (a   0) when  x =   1   a is
                                                                                                    2
                   y  = 4x(a – x).
                    2
                                                            3
                                                         3
                7.  Show that the differential equation xy 2 dy   – x  – y  = 0 can be transformed into the differential equation
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                     dv    1                       dx
                   x    =    by using the substitution y = vx. Hence, find the particular solution of the original equation
                     dx   v 2
                   given that x = 1, y = 1.
                                                                                      dy
                                                                                             2
                                              3
                8.  Show that the substitution v = x  + y transforms the differential equation (x – 1)   – 3x  – 3y = 0 into
                                       dv     3v                                      dx
                   the differential equation    =   . Hence, find the general solution to the original differential equation.
                                       dx   (x – 1)
                                     1                                dy
                9.  By substituting  z =    ,  transform  the differential equation    +  y  =  xy  into a  differential  equation
                                                                                 3
                                    y 2                               dx
                   containing z and x. Solve the equation for z, and, hence, show that the solution of the given differential
                                                                 1
                                                             2
                                       
                   equation for which y =  2  when x = 0 is y =  1 2x + 1 2 — 2 .
                                                                       dy
               10.  By substituting u = y , transform the differential equation 2xy    = y  – 4x  into a differential equation
                                                                                  2
                                    2
                                                                             2
                                                                       dx
                   containing u and x. Find the particular solution of the given differential equation for which y = a when
                   u =   1   a.
                       2
                                                              dy
               11.  By writing u =   1 , reduce the differential equation   dx   +   x y   = y  to   du  –   u  = –1.
                                                                        2
                                                                                  x
                                y
                                                                            dx
                   Hence, solve the original differential equation when x = 1, y = 1.
          4
                      4.5  Problems Modelled by Differential
                             Equations
              There are many physical situations in which different variables changes at different rates.  Differential equations
              always arise when we model these physical situations in mathematics. The following   situations show a few
              physical problems that involve differential equations.
              (a)  Assuming a particle falls from rest in a medium that causes the velocity to increase at a rate proportional
                  to its velocity. By denoting velocity as  v and time as  t,  the  rate  of  increase  of  velocity  can  be  written
                  as   dv  . Hence, the velocity of the particle satisfies the differential equation   dv  = kv.
                     dx                                                          dt
              (b)  The rate of decay of a radioactive substance is proportional to the amount of remaining   substance.
                  Hence, the amount of remaining substance, x at any time t can be found by  solving the  differential equation
                   dx   = –kx.
                   dt
              (c)  In a chemical process, a certain substance A continuously changes to another  substance B. The rate of such
                  a change is proportional to the mass of A and inversely  proportional to the mass of B, at any time t. The
                  total mass of A and B at any time remains constant and is equal to N. Hence, the mass of B, n, at time t
                  can be expressed by the differential equation   dn   =   k   (N – n).
                                                        dt   n
                                                                                                   2
              (d)  The rate of increase of a population due to birth is αx and the rate of decrease due to death is βx  where
                  x is  the population number at  time  t.  The population number at  any  time  can be  found  by solving  the
                                                2
                  differential equation   dx   = αx – βx .
                                    dt
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         04 STPM Math(T) T2.indd   140                                                                 28/01/2022   5:44 PM
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