Page 35 - Hybrid PBD 2022 Form 5 - Mathematics
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Matematik Tingkatan 5  Bab 6 Nisbah dan Graf Fungsi Trigonometri
                  7.  Selesaikan masalah berikut.   SP 6.1.4
                     Solve the following problems.

                      (a)  Dalam rajah di bawah,  MNP ialah garis lurus.  (b)  Dalam rajah di bawah,  QRST ialah suatu garis
                         Diberi RM = MN = NP = 7 cm, hitung    TP4        lurus dengan QR = RS. Diberi PR = √288 cm dan
                         In the diagram, MNP is a straight line. Given that RM = MN =   ∠RPQ = 50°, tentukan    TP5
                         NP = 7 cm, calculate                             In the diagram QRST is a straight line with QR = RS. Given
                         (a)  tan x                                       PR = √288  cm and ∠RPQ = 50°, determine
                         (b)  sin y                                       (a)  panjang, dalam cm, QS,
                                                                              the length, in cm, of QS,
                                   y
                                                                          (b)  nilai bagi kos ∠SPQ,
                                    R                                         the value of cos ∠SPQ,
                                                                          (c)  nilai kos x.
                                                                              the value of cos x.
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                                                x
                                   M    7 cm   N          P                  P

                                                                              50°
                         RN  = √MR  + MN
                                         2
                                   2
                             = √7  + 7 2                                                  288 cm
                                 2
                             = √98
                                                                                                               x
                                         R                                   Q                R                S  T
                                               98 cm
                                      7 cm                                              QR
                                                                          (a)  sin 50° =
                                                                                       √288
                                         M  7 cm  N
                                                                                 QR  = √288 × sin 50°
                                                                                      = 13 cm

                         (a)  90° , x , 180°                                     QS  = 2QR
                             Sudut x terletak di sukuan II                            = 2(13)
                             Angle x is located in quadrant II                        = 26 cm
                             tan x  = −tan ∠RNM
                                      7                                   (b)  PQ  = (√288)  − 13 2
                                                                                2
                                                                                         2
                                  = −
                                      7                                       PQ  = 119
                                                                                2
                                  = −1                                        PQ  = √119
                         (b)  270° , y , 360°                                 PS   = (√119)  + 26
                                                                                         2
                                                                                               2
                                                                                2
                             Sudut y terletak di sukuan IV                    PS   = 795
                                                                                2
                             Angle y is located in quadrant IV                PS  = √795
                             sin y  = −sin ∠MRN                                          PQ
                                        7                                     kos ∠SPQ =
                                  = −                                         cos ∠SPQ    PS
                                       √98                                                √119
                                  = −0.7071                                            =
                                                                                          √795
                                                                                       = 0.3869
                                                                          (c)  90° , x , 180°
                                                                              Sudut x terletak di sukuan II
                                                                              Angle x is located in quadrant II
                                                                              kos x = −kos ∠QSP
                                                                                 cos x = −cos ∠QSP
                                                                                        26
                                                                                   = −
                                                                                       √795
                                                                                   = −0.9221








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         06 Hybrid PBD Mate Tg5.indd   127                                                                        28/09/2021   5:15 PM
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