Page 35 - ACE YR IGCSE A TOP APPR' TO MATHS

2
= 2 4 (shown) 2 45 = 3 × 5

60 = 2 × 3 × 5
2
9 [2] (a) HCF = 3 × 5 = 15 [2]
4 22 + 5 (b) a = 5 [2]
7 3 3 72 = 2 × 3 2
3
= 66 + 35 60 = 2 × 3 × 5
2
21 96 = 2 × 3
5
= 101 (a) HCF = 2 × 3 = 12 [2]
2
21 (b) 5 [2]
= 4 17 4 160 = 2 × 5
5
21 [2] x = 2 × 5 2 [2]
5 4 ÷ 8 5 (a) 9000 = 2 × 3 × 5 3 [2]
3
2
9 3 (b) LCM = 2 × 3 × 5 = 18000
3
4
2
= 4 × 3 400m = 18000
9 8 m = 45 [2]
= 1 (c) n = 2 × 3 × 5 = 90 [2]
2
6 [2] 6 95 = 5 × 19
6 16 × 1 285 = 3 × 5 × 19
3 8 (a) HCF = 5 × 19 = 95
= 2 95 × 4 = 380 cm [2]
3 [2] (b) 285 ÷ 95 = 3 cards [2]
2
7 1 + 2 − 1 7 45 = 3 × 5
5 3 6 48 = 2 × 3
4
2
= 6 + 20 – 5 60 = 2 × 3 × 5
30 LCM = 2 × 3 × 5
4
2
= 7 = 720 seconds
10 [2] = 12 minutes
8 ( 5 + 5 ) ÷ 2 11:59 p.m. + 12 mins [3]
=12.11 a.m.
9
7
1
80
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=
×
63 2 Upper bound and lower bound
= 40 1 (a) (i) (PQ) = (3.285 × 4.5) = 218.52 [3]
2
2
63 [2] R – Q 0.0455 – 5.5
[(
9 1 − 5 − 1 − 5 ) × 4 ] (ii) P = 3.295 = –1.66 [3]
12 12 7 Q 4.5
= 1 − 5 − 1 (iii) P – R = 3.295 – 0.0455 = 1.38 [3]
12 3 P + Q 3.295 + 5.5
= 1 (b) (i) R = 0.0455 = 193.30 [3]
4 (ii) (R − Q) = (0.0465 − 4.5) = 19.83 [3]
2
2
(iii) Q = 5.5 = 36.80 [3]
Fraction of teachers over parents PR 3.285 × 0.0455
1 2 Area = 3.75 × 3.75 = 14.0625 cm 2
= 4 Perimeter = 3.75 × 4 = 15 cm [4]
5 3 Percentage increase
12 = 4.85 – 1.65 × 100%
1.65
= 3 = 193.94% [3]
5 [2] 4 Number of cups
10 625 g = 58 [2] = 1.5 l
1 kg 285 ml
= 5.26
Multiples and factors ≈ 5 cups
1.5 l − 0.285 l × 5 = 0.075 l or 75 ml [3]
1 (a) 2 × 3 × 7 = 21168 [2] 5 4.15 + 10.85 + 2.65
4
2
3
2
(b) 2 × 7 = 98 [2] = 17.65 cm [3]
2
4
(c) √2 × 7 = 2 × 7 = 28 [2] 6 Distance = 7.5 × 1.5
2
= 11.25 km [3]
Answers 155

Answers.indd 155 15/03/2022 11:08 AM