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125.5                                       3
                  7          = 12.55 km/l                   [3]         ξ
                      15 ×   2                                              A     B
                           3
                       Powers and roots

                  1   (a)  2 –2                             [2]                                              [2]
                      (b)  2  × 2  ÷ 2  = 2 2               [2]    4
                                  5
                           4
                              3
                      (c)  3  ÷ 3  × 3 = 3 14               [2]         ξ   A     B
                              –4
                                   6
                           4
                      (d)   5 8   = 5 –1                    [2]
                          5 9
                  2   (a)  A                                [2]
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                      (b)  E                                [2]                C                             [2]
                      (c)  B and C                          [2]
                  3   [7 + (–1)] – [(–4) ÷ 4] 121                  5    ξ
                      = 6 – (–1)                                            A     B
                              121
                      = 6 – (–1)
                      = 7                                   [3]
                  4    2  × 2  = 2 0                                           C
                       –9
                           2a
                       –9 + 2a = 0                                                                           [2]
                           a = 4.5                          [3]    6
                           2     1                                      ξ   A     B
                        2    3 + 3    3
                         3 ×
                               3 ×
                  5             1
                           2
                              2
                         (2  × 7 ) 2
                         2
                      =  2  + 3                                                C
                        2 × 7                                                                                [2]
                      =   1                                 [4]    7   (A ∪ B)’ ∩ C                          [3]
                        2
                          1      1  1                              8   A’ ∩ B ∪ C                            [3]
                  6   (5    2 – 17   1  3)  3
                               3 ×
                        4 ×
                      = (25 – 17) 3                                9   A ∪ B ∪ C’                            [3]
                      = 2                                   [3]
                  7   169 – √100
                                                                     1A
                      = 159  1  1 –1                        [3]      1B   Numbers
                  8   ( ( (2 )  ) 2 )                                            54
                         8 2
                      =   1                                 [3]    1   (a)  Time =  72  = 0.75 h = 45 min    [1]
                        4                                              (b)  Time =  54  =   3  h = 36 min
                  9   16 – 9  ×   8                                              90    5
                        27    8                                            45 – 36   × 100% = 20%            [2]
                      =   7                                 [3]              45
                        27                                         2   (a)  Amount received
                                                                           = (2000 × 1.85) × 0.99
                       Sets
                                                                           = $3663                           [2]
                  1    ξ                                               (b)  (i)  Amount received
                           A     B                                                = (2000 × 0.005 × 6) + 2000  [2]
                                                                              = $2060
                                                                          (ii)  Amount received
                                                                              = (2060 × 1.8) − $30
                                                                              = $3678                        [2]
                                                            [2]        (c)  Danny, by $15 more               [1]
                                                                       (d)  $500 ÷ $1.94
                  2    ξ                                                   = £257.73
                           A     B                                         = £258                            [2]
                                                                   3   (a)  (i)  $10000 × 0.3
                                                                              = $3000
                                                                              A : B : C
                                                                              2.1 : 1.5 : 3.6
                                                            [2]               7 :  5 : 12


                        Cambridge IGCSE
                                         TM
                  156     Ace Your Mathematics






         Answers.indd   156                                                                                      15/03/2022   11:08 AM
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