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Business + Education = 100% – 15% – 35% (d) Original airfare
= 50% = $250 × 100
Business content = 60 83
50% 90 = $301.20 [1]
Business content = 33 1 % [4] 12 ξ
3 A B
9 Let Y = each other art pieces that are sold 46 12 16
($150 × 0.68 × 50) + ($150 × 0.55 × 25) + ($150 ×
0.48 × Y) = 8000 35 5 2
Y = 11.63
8
Total amount of artwork C
Penerbitan Pelangi Sdn Bhd. All Rights Reserved.
= 50 + 25 + 12 [5]
= 87 [4] 13 (a) 6174 = 2 × 3 ×7 3 [2]
2
3
3
2
2
174 km (b) √2 × 3 × 7 × (2 × 3)
3
h 1740 km = √2 × 3 × 7
3
3
3
10 (a) (i) = [2]
6 h h 2 = 42
60 k = 2 × 3
2
( 46 – 4 + 52 ) (174) (c) 180 = 2 × 3 × 5 [2]
= 12
2
2
2
2
(ii) Distance = 60 60 2 × 3 × 5 × m = multiple of 2 × 3 × 7 3
2
2 m = 7 = 343
3
2
= 136.3 km [2] 180m = 2 × 3 × 5 × 7 3
2
(iii) Average speed = 61740 [2]
Total distance (d) 61740 = 2 × 3 × 5 × 7 3
2
2
= b = 2, c = 2, d = 5, e = 1
Total time a = 2 × 3 × 5
2
2
= 136.3 km = 180 [2]
52 h (e) 180 × f = 2 × 3 × 5 × f
2
2
60 = 2 × 3 × 5 × (2 × 3 × 5 )
2
4
4
2
5
= 157.269 km/h = 2 × 3 × 5 6
6
6
= 43.69 m/s [2] f = 4050000 [2]
(b) Time 14 (a) Time taken for the first part of the journey
1.1 km + 250 m
= = 30.9 s [2] 3 × 420
43.69 m/s 4
(c) Speed = 375 km = 60
156.5 min = 3 hours
= 143.77 km/h [2] Time taken for the second part of the journey
11 (a) (i) 4, 3, 7, 1 [2] 4
(ii) 12 [2] 7 × 420
979 =
(b) (i) Time = = 2.2 h 80
445 = 3 hours
10.10 a.m. + 2.2 h Total distance
= 10.10 a.m. + 2 h 12 min Average speed = Total time
= 12.22 p.m. [2] 420
(ii) 2.2 h × 7 = 3 + 3 + 0.25
11
= 132 min × 7 = 67.2 km/h [4]
= 84 min 11 (b) Speed of car B = 67.2 × 100
= 1 h 24 min [2] 105
(c) Fuel used = 64 km/h
= 979 km Time car B arrives at City Q
55 m/l = 21.30 + 420
= 979000 m 64
55 m/l = 21.30 + 6.5625
= 17800 l = 21.30 + 6 h 34 min
= 1.78 × 10 l [2] = 4.04 a.m. [3]
4
Cambridge IGCSE
TM
158 Ace Your Mathematics
Answers.indd 158 15/03/2022 11:08 AM