Page 84 - Hybrid PBD KSSM 2021 Tg 4 - Fizik

Fizik Tingkatan 4 Bab 2

(a) Momentum troli A (b) Momentum troli B (d) Momentum troli A (e) Momentum troli B
Momentum of trolley A Momentum of trolley B Momentum of trolley A Momentum of trolley B
= 2.5 × 2 = 3.2 × 2 = 2.5 × 0.2 = 3.2 × v B
= 5.0 kg m s –1 = 0 kg m s –1 = 0.5 kg m s –1 = 3.2v kg m s –1
B

(c) Jumlah momentum sebelum perlanggaran (f) Jumlah momentum selepas perlanggaran
The total momentum before collision The total momentum after collision
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= 5.0 + 0 = 0.5 + 3.2v B
= 5.0 kg m s –1

(g) Jumlah momentum sebelum perlanggaran = Jumlah momentum selepas perlanggaran
The total momentum before collision = The total momentum after collision
5.0 = 0.5 + 3.2 (v )
B
5.0 – 0.5 = v
3.2 B
v = 1.41 m s –1
B

4. Selesaikan masalah-masalah berikut. SP 2.5.2 TP3 KBAT Mengaplikasi
Solve the following problems.
(a) Peluru
Bullet
Peluru
Bullet Bongkah kayu
Wooden block
25 g
5 kg
100 m s –1 v

0 m s –1
Sebelum perlanggaran Selepas perlanggaran
Before collision After collision
Rajah di atas menunjukkan sebiji peluru berjisim 25 g ditembak ke arah sebuah bongkah kayu berjisim
5 kg dengan halaju 110 m s . Peluru dengan bongkah kayu bergerak bersama-sama selepas peluru
–1
terbenam di dalam bongkah kayu. Hitung halaju gerakan bongkah kayu dan peluru tersebut selepas
perlanggaran berlaku.
The diagram above shows a bullet a mass 25 g fired at a wooden block of mass 5 kg with a velocity of 110 m s . The bullet and the
–1
block of wood move together after the bullet is embeded in the block of wood. Calculate the velocity of motion of the block of wood
and the bullet after the collision occured.
Jumlah momentum sebelum perlanggaran = Jumlah momentum selepas perlanggaran
The total momentum before collision = The total momentum after collision
0.025(100) + 5.0(0) = v(0.025 + 5.0)
2.5 = v
5.025
v= 0.498 m s –1

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02 HYBRID PBD FIZIK F4.indd 43 05/11/2021 8:20 AM