Page 87 - Hybrid PBD KSSM 2021 Tg 4 - Fizik

Fizik Tingkatan 4 Bab 2

4. Hitung pecutan bagi blok di bawah. SP 2.6.2 TP3 KBAT Mengaplikasi
Calculate the acceleration of the block below.

(a) m = 2.5 kg (b) m = 15.8 kg
F 1 = 15.0 N F 3 = 7.0 N
F = 7.0 N
F 2 = 20.0 N

F = ma F = ma
7.0 = 2.5a – 15 – 20 + 7 = (15.8)a
a = 2.8 m s –2 –28 = (15.8)a
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a = –1.77 m s –2

5. Hitung nilai bagi F bagi setiap situasi di bawah. SP 2.6.2 TP3 KBAT Mengaplikasi
Calculate the value of force F for each situation below.
(a) a = 2.5 m s –2 (b) a = 4.0 m s –2

F = 12 N
1
m = 4.0 kg F F m = 8.0 kg F = 16 N
2
F = ma F = ma
= 4.0 (2.5) F – 12 – 16 = 8.0(4.0)
= 10 N F = 32 + 12 + 16
= 60 N

6. Selesaikan setiap masalah berikut. SP 2.6.2 TP3 KBAT Mengaplikasi
Solve the following problems.
(a)

Rajah di atas menunjukkan seorang penunggang motosikal menekan brek ketika bergerak pada halaju
–1
20 m s sehingga berhenti setelah melalui jarak sejauh 40 m. Jumlah jisim motosikal bersama penunggang
tersebut ialah 190 kg. Berapakah daya yang dikenakan oleh brek motosikal tersebut untuk berhenti?
The diagram above shows a motorcyclist pressing the brakes while moving at a velocity of 20 m s until it stops after going through a
–1
distance of 40 m. The total mass of the motorcycle with the rider is 190 kg. How much force applied by the brake to stop the motorcycle?
v = u + 2as Guna F / Use F = ma
2
2
0 = 20 + 2a(40) F = (190)(–5)
2
a = –5 m s -2 = –950 N

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02 HYBRID PBD FIZIK F4.indd 46 05/11/2021 8:20 AM