Page 35 - Ranger SPM 2022 - Additional Mathematics
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Additional Mathematics  SPM  Chapter 2 Differentiation

                Example 16
                                 1
                Given that y = 3x +  , and x changes from 2 to 1.98, find
                                 x
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                (a)  the approximate change in y,
                (b)  the approximate value of y.
                  Solution
                            1                                                 1
                (a)  y = 3x +  x                      (b)  When x = 2, y  = 3(2) +  2
                      = 3x + x –1                                     =  13
                    dy                                                   2
                        = 3 – x –2
                    dx                                               dy      1
                    When x = 2 and δx = 1.98 – 2         When x = 2,   dx  = 3 –  2 2
                                    = –0.02                             = 2.75
                    δy   dy  × δx                        f(x + δx)  y +   dy δx
                         dx
                                                                       dx
                        
                    δy =  3 –  x 1 2  × (–0.02)                  =  13  + 2.75(–0.02)
                                                                    2
                        
                       = 3 –  2 1 2  × (–0.02)                   = 6.445
                       = 2.75(–0.02)
                         = –0.055





                                             Mastery


                 1.  The diagram below shows a plate which    Solution
                    is  made  up  of  a  rectangle  ABCD  and
                    semicircles at both ends. The area of the   (a)  Let y = diameter of the semicircle
                    rectangle is 200 cm .                       Perimeter of the plate,
                                   2
                                                                P = 2x + 2πr
                             A            B
                                                                  = 2x + πy
                                                                  Area of ABCD = 200
                                                                          xy  = 200
          Form 5            D     x cm    C                                y =  200
                                                                                x

                    (a)  Show that  the perimeter,  P of the    Hence, P = 2x + πy 200
                       plate is P = 2x +   200π  .                      = 2x + π   x  
                                        x
                    (b)  Find the minimum perimeter P and               = 2x +  200π
                       the corresponding value of x.                            x
                                                            (b)  P = 2x + 200πx –1
                                                                dP       200π
                                                                    = 2 –
                                                                dx        x 2
                                                    188





         02 Ranger Mate Tambahan Tg5.indd   188                                             25/02/2022   9:23 AM
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