Page 191 - SK Year 5 Mathematics DLP
P. 191

SUBTRACTION OF UNITS OF LENGTH



                   1    a   What is the difference in height          62.7 cm                  3   cm
                           between Robot R and Robot S?                          54.9 cm       5
                                                                                              shorter
                           62.7 cm – 54.9 cm =            cm
                                                                                              than
                                  11
                                5 1 17                                                        Robot S
                                62.7 cm
                             – 54.9 cm
                                 7.8 cm                            R           S         T

                           62.7 cm – 54.9 cm =  7.8  cm
                           The difference in height between Robot R and Robot S is 7.8 cm.

                        b   Calculate the height, in mm, of Robot T.
                                        3
                           54.9 cm –   cm =            mm
                                        5
                                           3                             3    2
                              54.9 cm –   cm = (54.9 × 10) mm – (  × 10) mm
                                           5                             5
                                                 = 549 mm – 6 mm         1
                                                 = 543 mm
                                        3
                           54.9 cm –   cm =  543  mm
                                        5
                           The height of Robot T is 543 mm.


                                           4
                   2   2.07 m – 16 cm –   m =           m
                                           5
                                                                  First, convert the measurement in
                       16 cm = (16 ÷ 100) m           0.8 m          decimal m. Then, subtract.
                                                   5 4.0 m
                              = 0.16 m
                                                     −0                                 1 10
                                                      4 0                               2. 0 7 m
                                                     −4 0                             – 0. 1 6 m
                                                         0
                                                                                        1 . 9 1 m
                                                                                      – 0. 8 0 m
                                              4                                         1 . 1 1 m
                          2.07 m – 16 cm –   m =  1.11  m
                                              5




                                   • Encourage pupils to subtract by finding the balance or difference
                                     of length of an object.                                          183
                             5.1.4
                                   • Ask pupils to carry out the required conversion of unit of length
                                     according to the questions.
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