Page 186 - SK Year 5 Mathematics DLP

The width of this kite is 1.37 m.
Centimetres and metres

1 Convert 1.37 m to cm.

1.37 m = cm

1.37 m = (1.37 × 100) cm

= 137 cm

1.37 m = 137 cm

1
2 1 m = cm
4
Method 2
Method 1 5
1
1 1 1 m = ( × 100) cm
1 m = 1 m + m 4 4
4 4
1 25 = (5 × ) cm
= (1 × 100) cm + ( × 100) cm
4
1 = cm
= 100 cm + 25 cm

= 125 cm Does method 2 give
1
1 m = 125 cm the same answer?
4

3 39 cm = m 4 5 m 80 cm = m

39 cm = (39 ÷ 100) m 5 m 80 cm = 5 m + (80 ÷ 100) m
= 0.39 m
= 5 m + 0.8 m
39 cm = 0.39 m
= 5.8 m

5 m 80 cm = 5.8 m
1 m = 100 cm
× 100
4
5.8 m is equal to 5 m. Prove it.
m cm 5

÷ 100

• Encourage pupils to appreciate traditional games such as wau, gasing,
178 5.1.1 (ii) and congkak.
5.1.2 (ii) • Use various methods to state the relationships between units involving
fractions and decimals.