Page 52 - SK Year 5 Mathematics DLP
P. 52

Find the balance after buying
                  3              2 persons generously
                                donated RM3 000 each.       the bookcases.
                                                            2 × RM3 000 − RM1 200 =

                                                               Step 1                Step 2


                                                                 RM3 0 0 0                5 10
                                                               ×            2         RM6 0 0 0
                                                                 RM6 0 0 0          – RM1 2 0 0
                                                                                      RM4 8 0 0


                                                            2 × RM3 000 − RM1 200 =  RM4 800
                    RM1 200 will be used
                     to buy bookcases.                      The balance after buying the
                                                            bookcases is RM4 800.


                 4  (100 − 20) × 3 =                         5  (300 − 25) × (24 − 11) =


                    Step 1            Step 2                    (300 − 25) × (24 − 11)            2 1

                         1 0 0              8 0                 =     275 × 13              ×     2 7 5
                                                                                                    1 3
                     –    2 0         ×       3                 = 3 575                        1 8 2 5
                          8 0            2 4 0
                                                                                            + 2 7 5 0

                     (100 − 20) × 3 =  240                                                     3 5 7 5


                    Operations in the brackets                  (300 − 25) × (24 − 11) =  3 575
                       must be solved first.


                                                                  60 − 17 × 3 = 129
                                                       The number sentence above is wrong.
                                                       Correct the number sentence.




                Solve these.

                 a  16 − 2 × 5 =               b  32 × 7 − 102 =          c  900 − 215 × 4 =

                 d  24 139 − 916 × 8 =         e  (407 − 93) × 6 =        f  809 × (82 − 56) =
                 g  (3 010 − 59) × (200 − 195) =          h  (7 103 − 2 016) × (500 − 431) =




              44
                              1.7.1 (ii) • Emphasise that operations in the brackets must be solved first.
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