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UNITS AND MEASUREMENT                                                                       27

                                                                 Then,
                  Example 2.9  The resistance R = V/I where             ∆Z/Z = (∆A/A) + (∆A/A) = 2 (∆A/A).
                 t
                  V = (100 ± 5)V and I = (10 ± 0.2)A. Find the   Hence, the relative error in A  is two times the
                                                                                              2
                  percentage error in R.
                                                                 error in A.
                Answer  The percentage error in V is 5% and in   In general, if   Z = A  B /C r
                                                                                       q
                                                                                    p
                I  it is 2%.  The total error in R would therefore  Then,
                be 5% + 2% = 7%.                            t            ∆Z/Z = p (∆A/A) + q (∆B/B) + r (∆C/C).
                  Example 2.10  Two resistors of resistances     Hence the rule    : The relative error in a
                 t
                  R  = 100 ±3 ohm and R  = 200 ± 4 ohm are       physical quantity raised to the power k is the
                                        2
                    1
                  connected (a) in series, (b) in parallel. Find  k times the relative error in the individual
                  the equivalent resistance of the (a) series    quantity.
                  combination, (b) parallel combination. Use
                  for (a) the relation R = R + R  and for (b)      t  Example 2.11   Find the relative error in
                                          1   2,
                                                                    Z, if Z = A B 1/3 /CD 3/2 .
                                                                             4
                               and
                                                                 Answer    The relative  error in Z  is  ∆Z/Z  =
                Answer  (a) The equivalent resistance of series  4(∆A/A) +(1/3) (∆B/B) + (∆C/C) + (3/2) (∆D/D).
                combination                                                                                  t
                R = R + R =  (100 ± 3) ohm + (200 ± 4) ohm
                     1   2                                         t  Example 2.12  The period of oscillation of
                             = 300 ± 7 ohm.                        a simple pendulum is T = 2π          L/g.
                (b) The equivalent resistance of parallel          Measured value of L is 20.0 cm known to 1
                combination                                        mm accuracy and time for 100 oscillations
                       R R     200                                 of the pendulum is found to be 90 s using
                  R′=    1  2  =     = 66.7 ohm                    a wrist watch of 1 s resolution. What is the
                      R +  R    3
                        1   2                                      accuracy in the determination of g ?
                              1   1    1                                        2    2
                  Then, from  R′  =  R 1  +  R 2                 Answer   g = 4π L/T    t ∆           ∆     t ∆
                                                                           t
                  we get,                                        Here, T =   n   and  T∆ =  n  . Therefore,   T T  =  t  .
                   ∆ R′  =  ∆ R 1  + ∆ R 2                       The errors in both L and t are the least count
                   R′ 2  R  2  R  2                              errors. Therefore,
                                2
                          1
                                                                 (∆g/g) = (∆L/L) + 2(∆T/T )
                            )
                                      )
                                                                            .
                  ∆ R′ = ( R′ 2 ∆ R 1  + ( R′ 2 ∆ R 2                      0 1      1 
                                                                                          .
                             R 1 2      R 2 2                            =   20 0  +  2    90   = 0 027
                                                                             .
                         66.7  2    66.7  2                  Thus, the percentage error in g is
                      =
                               3 +       4                          100 (∆g/g) = 100(∆L/L) + 2 × 100 (∆T/T )
                          100       200 
                                                                                  = 3%                       t
                      = 1.8
                                                                 2.7  SIGNIFICANT FIGURES
                                  ±
                  Then, R′ =  66.7 1.8 ohm
                  (Here, ∆R is expresed as 1.8 instead of 2 to   As discussed above, every measurement
                keep in confirmity with the rules of significant  involves  errors. Thus, the result of
                figures.)                                  t     measurement should be reported in a way that
                                                                 indicates the precision of measurement.
                                                                 Normally, the reported result of measurement
                (c) Error in case of a measured quantity         is a number that includes all digits in the
                   raised to a power
                                                                 number that are known reliably plus the first
                Suppose   Z  = A ,                               digit that is uncertain. The reliable digits plus
                               2





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