Page 26 - Trigonometry
P. 26
The area of the two blue triangles is given by,
2
2
1 √ − 2 √ − 2
2 × × × =
2 2 2 4
The area of the circle sector (the sum of the blue and
the red) is,
2
( )
2 2
However from Eq:1.
= sin −1 ( )
2
The sector area becomes
2
( ) sin −1 ( )
2
The red area is,
22
