Page 44 - Integration Problems

Example 11:

Perform the following integration,

/3
3
∫ sec ( ) tan( )
/6

Express as,

/3 1 sin( ) /3 sin( )
∫ 3 = ∫ 4

/6 cos ( ) cos( ) /6 cos ( )

Let

= cos( )

Then

= − sin( ) and − =
sin( )

The integral becomes

/3 sin( ) /3 sin( )
∫ 4 = − ∫ 4
/6 cos ( ) /6 cos ( ) sin( )

This becomes,

/3
3 3 −3
− ∫ = − ∫ −4 = [ ]
4 3
6 6 /6
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