Page 49 - Integration Problems

Example 13

Evaluate the integral

3

∫ ln(1 + )

0
Perform integration by parts

∫ = − ∫

Let = ln(1 + ) and =

1 2
Then = and = ∫ =
+1 2

3 3 3
2 1 2
∫ ln(1 + ) = [ ln(1 + )] − ∫
2 2 + 1
0 0 0
In the integral need to divide the numerator by the

denominator.
_x_- 1____

x + 1|x 2

2
x + x
-x

-x - 1

1

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