Page 8 - Integration Problems
P. 8
Equate coefficients,
1 =
0 = +
= −1
1 1 1
= + = −
( + 1) + 1 + 1
1 /3 1 1 1
∫ = ∫ [ − ]
2 0 ( + 1) 2 0 + 1
Perform the integration,
1 1 1
∫ [ − ]
2 + 1
0
1 /3
= [ln( ) − ln( + 1)]
2 0
1 /3
= [ln ( )]
2 + 1 0
2
2
Since = cos ( )
4
