Page 11 - Integration Problems

Example 2:

Perform the following integration,

2 ln( )
∫ 2
1 ( − 3)

This integration can be solved by using integration by

parts which involves the variables u and v so that,

2 ln( )
∫ 2 = ∫ = − ∫
1 ( − 3)

then

−2
= ln( ) and = ( − 3)

1 1
−2
= and = ∫( − 3) = −
( − 3)

2 ln( ) ln( ) 2 2
∫ 2 = − [ ] + ∫

1 ( − 3) ( − 3) 1 1 ( − 3)

Partial fractions,

1
= +
( − 3) − 3

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