Page 10 - Integration Problems

Which now feeds into the second Stage.

1 Ans 1
= [ln ( ) − ln ( )]
2 Ans + 1 2

1a2$(hMaM+1$)p
h1a2$))==

Confirm this result, consider the original integral

/3
1 − tan( )
∫
2
2
cos ( ) + 1
0
The keystrokes to perform this Integration are:

ya1plQ(X))RqH2J(X)
$kJ(X))d+1R0EqLP

3=

As you can see the two calculations produce the same

result which suggests the integration is correct.

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