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MODULE • Chemistry Form 4

             6   The diagram below shows list of chemical substances.
                 Rajah di bawah menunjukkan senarai bahan-bahan kimia.
                            Hydrochloric acid, 1.0 mol dm –3   Barium chloride solution, 1.0 mol dm –3
                            Larutan asid hidroklorik, 1.0 mol dm –3  Larutan barium klorida, 1.0 mol dm –3
                            Iron(II) sulphate solution, 1.0 mol dm –3  Solid copper(II) oxide  Solid calcium carbonate
                            Larutan ferum(II) sulfat, 1.0 mol dm –3  Pepejal kuprum(II) oksida  Pepejal kalsium karbonat

                 (a)  (i)   Choose two solutions that can be used to prepare insoluble salts.
                          Pilih dua larutan yang digunakan untuk menyediakan garam tak terlarutkan.
                          Barium chloride and iron(II) sulpahate
                     (ii)  What is the type of reaction for the preparation of the salt in (a)(i)?
                          Apakah jenis tindak balas bagi penyediaan garam di (a)(i)?
                          Double decomposition reaction

                     (iii)  Write the ionic equation for the production of the salt in (a)(i).
                          Tulis persamaan ion bagi penghasilan garam di (a)(i).
                          Ba + SO         BaSO
                                   2–
                            2+
                                  4           4
                     (iv)  Describe how to collect the pure salt produced.
                          Huraikan bagaimana anda mendapatkan pepejal garam tulen yang terhasil.
                          Filter the mixture and rinse with distilled water

                 (b)  State  the  observations  when  sodium  hydroxide  solution  is  added  in  small  amount  until  in  excess  into  iron(II)
                     sulphate solution./ Nyatakan pemerhatian anda apabila larutan natrium hidroksida ditambah sedikit sehingga berlebihan kepada
                     larutan ferum(II) sulfat.
                     Green precipitate formed, insoluble in excess of sodium hydroxide solution

                 (c)  (i)   Choose two chemical substances that can react to produce carbon dioxide gas.
                          Pilih dua bahan yang boleh bertindak balas untuk menghasilkan gas karbon dioksida.
                          Calcium carbonate and hydrochloric acid
                     (ii)  Write a balanced chemical equation for the reaction in (c)(i).
                          Tulis persamaan kimia seimbang bagi tindak balas di (c)(i).
                          CaCO + 2HCl      CaCl + H O + CO
                              3               2   2      2

             7   You are given zinc chloride crystals. Describe how you would conduct a chemical test in the laboratory to identify the ions
                 presence ions in zinc chloride crystals./ Anda diberi hablur zink klorida. Huraikan bagaimana anda boleh menjalankan ujian kimia di
                 dalam makmal untuk mengenal pasti ion-ion yang hadir dalam hablur zink klorida.
                                   1
                 –     Dissolve      spatula zinc chloride crystals in 10 cm  of   distilled   water.
                                                                     3
                                   2
                                  1
                       Larutkan     spatula hablur zink klorida di dalam 10 cm 3   air suling  .
                                  2
                 –  The    solution   is poured in three test tubes./   Larutan   tersebut dituang ke dalam tiga tabung uji.
                 –  Add a few drops   sodium hydroxide   solution are added to zinc chloride   solution   until excess. A white
                   precipitate soluble in excess of   sodium hydroxide   solution.
                   Tambahkan  beberapa  titik  larutan   natrium hidroksida    ke  dalam   larutan    zink  klorida  sehingga   berlebihan  .
                       Mendakan putih   larut dalam larutan    natrium hidroksida   berlebihan.
                 –  Add a few drops   ammonia    solution are added to another zinc chloride   solution   until excess. A white
                   precipitate soluble in   excess   of   ammonia     solution. Ions present are   zinc ions  .
                   Tambahkan beberapa titik larutan   ammonia   ke dalam   larutan   zink klorida yang lain sehingga   berlebihan  .
                       Mendakan putih   larut dalam larutan   ammonia   berlebihan. Ion yang hadir adalah   ion zink  .
                 –  About 2 cm  of dilute   nitric acid   is added to 2 cm  solution of chloride ions followed by 2 cm  of   silver nitrate
                                                                                                    3
                                                                 3
                            3
                   solution. White precipitate formed. Ions present are chloride ions.
                   2 cm 3   asid nitrik   cair ditambahkan kepada 2 cm  larutan ion klorida diikuti dengan 2 cm  larutan   argentum nitrat  .
                                                                                             3
                                                               3
                   Mendakan putih terbentuk. Ion yang hadir adalah ion klorida.
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           Nilam Publication Sdn. Bhd.

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