Page 3 - Spotlight A+ Physics Form 4.5

TAG OF 'TRY QUESTION...
IN FORMATIVE ZONE...' Form 5 Physics Chapter 3 Electricity
9. The resistance of a wire is directly proportional
to its resistivity, ρ (Ω m) and length, l (m) but Example 17
inversely proportional to the area of cross- A copper wire with the length of l and diameter d
section, A (m 2 ), that is has the resistance of R. What is the resistance of
R ∝ ρl and R ∝ 1 — A another copper wire with length 2l and diameter
Tag placed at the end of By combining the relationships shown, therefore 1 — 2 d in terms of R?
R = ρl
—–
Solution
examples to guide students Example 15 A Both wires are of the same material, therefore, the
resistivity, ρ, are the same.
For the first wire, area of cross section,
What is the resistance of a copper wire with a A = π × 1 — 2 2 d 2 Form
in answering related diameter of 0.5 mm and length of 2 m? = πd 2 —— 4 5 Physics Chapter 6 Nuclear Physics
Assume that the wire has the shape of a cylinder.
Resistivity of copper = 1.60 × 10 –8 Ω m.
∴ Resistance, R = ρl
6.1
Solution
CHAP
questions in Formative Zone. Length, l = 2 m = ρl —– A ——– 1. Fill in the blanks to complete the following radioactive decay equation. C1 228 Ra → 0
3
πd 2
Area of cross-section, A
(c)
+ –1 e
(a)
(b)
→ 1 p + –1 e

209 Po → 205 Pb +
0
88
84
82
1
= π × 1 —————– 2 2 = 4ρl —— 4 2. Calculate the number of α and β particles that are emitted from the radioactive decay series of
0.5 × 10 –3
2
= 1.96 × 10 –7 m 2 ——– 238 U → ... → 206 Pb C4
πd 2
Resistance of wire, R = ρl —– A For the second wire, area of cross section, Aʹ 3. Table 6.2 shows the record of the activity of a radioactive sample stored in the laboratory.
92
82
———————–
= 1.60 × 10 –8 × 2 1 —d 2 Table 6.2
1.96 × 10 –7 = π × 1 2
= 0.163 Ω ——–2 Date 15 March 2021 25 March 2021 4 April 2021
2
= πd 2 Activity / s –1 1 520 380 95
Try question 9 in Formative Zone 3.2 —— 16 (a) Calculate the half-life, T 1 — of the radioactive sample. C2
2
Example 16 ∴ Resistance = ρ × 2l A (b) Sketch a radioactive decay curve for the sample. C3
———–
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Wire X with the length of 120 cm and the cross- = ρ × 2l
©PAN ASIA PUBLICATIONS
section area of 0.80 mm 2 has the resistance of ———– FORMATIVE ZONE
πd 2
3.2 Ω. Calculate the resistivity of wire X. —— 16 6.2 Nuclear Energy
Solution = 8 × 4ρl ——– 1. Nuklear energy is an atomic energy, which is Nuclear fusion
Length, l = 120 cm πd 2 energy that tied the nucleus of an atom. http://bit.ly/2Kb1gBy
= 1.2 m = 8R 2. This energy is released during nuclear reactions
such as radioactive decay, nuclear fission and
SPM SIMULATION Area of cross-section, A Try question 11 in Formative Zone 3.2 nuclear fusion. 3. The loss of mass (mass defect) occurs during
these nuclear reactions. Questions to test
= 0.80 mm 2
= 0.80 × 10 –6 m 2
Resistance, R = 3.2 Ω
Nuclear Fission
students' understanding
HOTS QUESTIONS Resistance of wire, R = ρl —– A Ensure units are converted to S.I. while performing Nuclear fission 1. Nuclear fission is a nuclear reaction when a
http://bit.ly/3mqw0vm

= 3.2
heavy nucleus splits into two or more lighter
and stable nuclei while releasing a large amount
ρ × 1.2
0.80 × 10 –6
For example,
—————— = 3.2 the calculation. of energy. at the end of each
ρ = 2.13 × 10 –6 Ω m
1 cm 2 = 1 × 10 –4 m 2 Form A barium–141 nucleus, a kripton–92
Try question 10 in Formative Zone 3.2 1 mm 2 = 1 × 10 –6 m 2 Chapter 6 Light and Optics Physics 4 nucleus and three neutrons are produced.
A uranium–235 Energy is also released.
Provides complete solution 334 SPM Simulation HOTS Questions nucleus is bombarded An unstable uranium–236 + + + subtopic.
nucleus is produced.
by a neutron.
3.2.3
3.2.6
+
92 Kr
1. Figure 1 shows refraction of light when the + + + + + + + + + + + + + + + + + + + 36
CHAP
light travels from air to plastic.
with examiner's comment Incident ray 6 1 n Examiner's Comment: + + + + + + + + + + + + + + + + + + + Energy 3 1 n 0
+
+
+ +
+
+ + + +
+ + + +
+ + Light travel slower in medium with high
+
+
+ + + + +
+
+
+
+ +
+ +
+
+ + + + + +
0 optical density. When the ray of light
235 U
enters the plastic medium, the ray bends ++ + + + + + + + +
92
to help students to answer Plastic Air refraction is smaller than incident ray. If + + + + + + + + + + + 141 Ba 56
236 U
towards the normal. Therefore, angle of
92
the plastic is replaced with less dense
medium, the bending of ray of light will 36 0
235 U + 1 n → 236 U → 141 Ba + 92 Kr + 3 1 n + energy
0
92
92
56
be reduced.
HOTS questions. Figure 1 Answer: D
Figure 6.8 Nuclear fission involving uranium-35 bombarded by a single neutron
Which is the correct pathway of the light when 452 2. Figure 2 shows the position of an image 6.2.1
plastic is replaced with less dense medium? formed by a concave lens. Which position of
A C A, B, C or D, the viewer cannot see the image?
B
Form A
5 C
Chapter 4 Electromagnetism Physics Object Image

D
B D Figure 2
SPM MODEL PAPER
Paper 1 Examiner's Comment:
Virtual image is the image that cannot
be formed on the screen.Therefore, the
1. Which diagram shows the correct catapult field? What needs to be done so that the conductor virtual image is not visible on the same
C2 moves to the right with a larger angle of side as the object. Paper 1
A C S deflection? C2 Answer: A [40 marks]
U U U U S S S
A Reverse the poles of the magnet and increase Instruction: Answer all questions.
the value of the current
B Maintain the poles of the magnet and
decrease the value of the current 3. Figure 3 shows the situation at the junction where Which of the following is a base unit A The gradient of the graph is a — b
1.
U C Reverse the direction of the current and
S S S S U U U car P is turning left while car Q is moving toward A kJ B p increases linearly with q
B D decrease the strength of the magnet the junction. The driver in car P cannot see car B µm House Car P C If q = 1 then p = a — b + c
U U U U S S S S D Maintain the direction of the current and Q because the view is obstructed by the house C cd
increase the strength of the magnet wall on the roadside. To overcome the problem D The equation of the graph is p = a — b q + b — a
2.
4. Figure 2 shows the force, F acting in the direction faced by driver P, an appropriate mirror need to be Which of the following is a derived quantity?
installed in the correct place.
I
Mass of a satellite
S on a current-carrying conductor in a magnetic (a) In Figure 3, mark Y, where the mirror need to be II Proton charge 5. Assume that the length, L, time, T and density,
field. placed. Give one reason for the answer. Wall ρ are chosen as the new base quantities of a
S S S S U U U U P (b) State the suitable mirror to be used. Give one III Electrical power physics, what is the relationship of the derived
A I and II only
reason for the answer.
quantity of mass in terms of ρ, L and T?
(c) State one feature of the mirror suggested in B I and III only
Car Q
Q
SUMMATIVE ZONE 2. A current-carrying conductor is placed in a C3 F Current 3(b) so that driver P can see the clearer image. C II and III only Figure 3 CHAP A ρL 3 3 (ρLT)
magneticfield produced by a pair of Magnadur
B LT 3
magnets.
CHAP
6 C ρ 3 L
3. The following statement provides information
4
A magnetic force acts on the conductor if
D ABBBB
A the direction of the magnetic field is the
same as the direction of the current. S about a particular system. 213 6. Figure 2 shows five steel balls P, Q, R, S and T
B the direction of the magnetic field is opposite The coordination of systems of measurement with the same densities and size. SPM MODEL PAPER
to the direction of the current. R units worldwide facilitates the field of
C the direction of the magnetic field is Figure 2 science, sports, trade, medicine and so on.
Questions of various levels What is the direction of the magnetic field?
perpendicular to the direction of the
current.
C3
3. Figure 1 shows the arrangement of apparatus to A P Which is the system mentioned above? P
A Metric System
B R
study the effect of the force acting on a current-
of thinking skill to evaluate C Q B Imperial System Q R S T SPM MODEL PAPER
carrying conductor in a magnetic field. The
C Universal Measurement System
D S
conductor moves to the left with a small angle D International System of Units
of deflection when current flows in the direction 5. Figure 3 shows a current-carrying conductor
students' understanding Current between the poles of a permanent magnet. 4. Figure 1 shows the relationship between the When ball P is pulled to the left, released and hit
Figure 2
that shown.
physical quantities of p and q.
Force – + p ball Q with a displacement, the ball P becomes
stationary while the ball T moves forward with
of each topic. S N a situation. SPM-oriented practice
the same displacement. Give a reason for this
A Impulsive force before collision = Impulsive
based on latest SPM
N Conductor (0, c) b force after collision
Magnet B Velocity of ball P before collision = Velocity
Figure 3 q of ball T after collision
S Which action will make the conductor 0 C Kinetic energy before collision = Kinetic
energy after collision
Figure 1 experience a force downwards? C1 Figure 1 D Momentum before collision = Momentum
Which of the following statements is incorrect? format to assess students
Form after collision
4 Physics Chapter 6 Light and Optics 397
on all the topics learnt in
Reinforcement & Assessment of Science Process Skills 503
1. In this experiment, you will determine the value of refractive index for water.
Carry out the following instructions, refering to Figure 1. Observer Form 4 & 5 textbooks.
10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30
Ruler
Retort stand Beaker
Water
REINFORCEMENT & ASSESSMENT Cork 9 8 7 6 5 4 3 2 1 Image pin P o Complete answers
http://bit.ly/3bHkxpp
Pin P o
Pin P 1 0 cm ANSWERS
Figure 1
SCIENCE PROCESS SKILL (a) Carry out the experiment according to the following instructions Chapter 1 Measurement (b) (i) Duration, T = 24 = 1.2 s —— 20
FORM 4
(i) Fix a pin P o at the bottom of the beaker with cellophane tape.
(ii) Fill the beaker with water until P o is at a depth of 6.0 cm from the water surface.
10
1. D 2. A 3. A
(iii) Adjust pin P i so as it is in line with the image of P o (no parallax between pin P i and image of P o ). Paper 1 7. A 8. C 4. A 9. B 10. C 5. D (ii) l = ————––— × (1.2) 2
6. B
4 × (3.142) 2
(iv) Measure the distance y between pin P i and the bottom of the beaker. 1.1 11. B 12. D 13. C 14. B 15. D = 0.36 m
(v) Calculate the apparent depth, h = H – y. 1. (a) Length 16. D 17. C 18. A 19. B 20. C
(vi) Repeat the experiment by varying the real depth, H = 8.0 cm, 10.0 cm, 12.0 cm and 14.0 cm. (b) Base unit: Meter; 21. A 22. B 23. A 24. B 25. D Section B
4. (a)
Record all the readings in the Table 1.
Symbol of unit: m

Questions for students to master the Table 1 Apparent depth, h / cm 2. (a) Scalar quantity has magnitude Paper 2 Base quantity S.I. unit Car A Speed of car / m s –1

Magnitude: 1.55;
Section A

Symbol of physical quantity: l
30.00
1. (a)
Real depth, H/ cm
y / cm
6.0
only and vector quantity has both
meter
science process skill (SPS) presented in (b) Scalar quantities: Distance, speed, Length kilogram B C D 37.49 25.20 33.30
magnitude and direction.
Time
8.0
second
10.0
Mass
time
12.0

Vector quantities: Acceleration
————
Science Practical Test. Scan the QR code 3. Base quantities: Time, mass, length (b) P = Force × Length —– s (b) Both of them use walkie talkie
E
24.20
Time
14.0
= kg m
———— × m
Derived quantities: Volume, area
s × s
or smart phone. The time taken
= kg m 2 s –3
(b) Plot a graph of H (y-axis) against h (x-axis). Start your axes from the origin (0,0). Draw a best-fit line.
below to get Tip dan Teknik Prihatin Murid FORM 4 ANSWERS 1. (a) Graph functions as a visual tool (c) S.I. unit is not same as metric to pass through point O and P is ANSWERS
recorded and the time interval, t
(c) (i) Based on the graph drawn in 1(b), determine the value of the refractive index for water.
unit because the time unit cannot
is determined or other reasonable
1.2
be expressed in terms of 10.
(ii) State two precautions that you took in this experiment in order to obtain reliable readings.

For example, 1 hour = 60 minutes
method.
to represent the relationship
in answering Science Practical Test. (b) Steps to analyse graph: = 60 × 60 seconds (c) Malaysia speed limit

= 110 km h –1
= 3 600 seconds.
between two physical quantities.

CHAP
Metric unit is based upon power
= 30.56 m s –1
6

Thus, car B exceeds the speed
(i) State the relationship
units of time cannot be expressed
between two variables of tens or decimal-based but S.I. limit on Malaysia highway.
in terms of 10.
(d) Use the ultrasound detector,
(ii) Determine the gradient of 2. (a) (i) Base quantity: Mass Complete answers are
time tracker application or other
224 graph reasonable method. Record
(iii) Determine the area under (ii) Derived quantity: Force several readings on speed within
(iii) Vector quantity: Force
the graph (b) S.I. unit G provided. Scan QR code to
5 km and calculate the average
Tip dan Teknik (iv) Determine the value of = Fr 2 ——— 5. (a) In old system: F = mlt –2
values.
a physical quantity from
interpolation
m = Ft 2 l –1
Mm
(v) Make a prediction through = ———————– so, In new FAω system: l = A 2 , 1 —
kg m × m 2
s × s × kg × kg
extrapolation
Prihatin Murid 2. (a) V increases = kg –1 m 3 s –2get explanations for objective
t = ω –1
– 1 — 2

so, m = Ft 2 l –1 = Fω –2 A
(b) V= 0 cm 3 , θ = –250 °C 3. (a) (i) Time taken, T = 26 – 2 (b) There is no suitable measuring
= 24 s
θ = 300 °C, V =22 cm 3 (ii) To get the value of one device to measure force, area and
https://bit.ly/2JfnKAo V / cm 3 complete oscillation questions.
frequency accurately.
– There is no standard tool and
accurately.
standard objects to determine
30 (iii) Repeat the experiment to get force, area and frequency.
22 cm 3 20 the average value of two sets – The unit for derived quantity
of readings for 20 complete
becomes very complex and
10
–250°C oscillations. Use electronic or hinders the communications
θ / °C digital stopwatch to measure between physicist.
–300 –200 –100 0 100 200 300 the time more accurately. – or other reasonable answers.
520
iii