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(b)                 S                           (c)
                         P                      OR = 2OP                                         Q
                                                Perimeter rantau
                                                berlorek
                               O
                                  1.5 rad       Perimeter of the shaded
                                                region                                             θ
                             j
                                                = 21 cm                          R         O     j    P
                         Q
                                                                        Perimeter rantau berlorek
                                        R
                                                                        Perimeter of the shaded region
           SP 1.2.2    2j + 2j + 1.5(2j) + j + j + 1.5j = 21            = 16π + 24
                                                                        OP = OQ = QP
                                          10.5j = 21                    º q = 60° =  π
                                              j = 2 cm                             3
                                                                                     π
                                                                                π
                                                                           2
                                                                        j +  πj +  j +  j + j = 16π + 24
                         ©PAN ASIA PUBLICATIONS
                                                                           3    3    3
                                                                                       4
                                                                                  2j +  πj = 4(4π + 6)
                                                                                       3
                                                                                   6j + 4πj = 12(4π + 6)
                                                                                   j(6 + 4π) = 12(4π + 6)
                                                                                         j = 12 cm

                6.  Tentukan panjang perimeter bagi tembereng yang berlorek berdasarkan maklumat yang diberi.
                   Determine the length of perimeter for the shaded segment based on the given informations.  TP 4

                                                    (a)                              (b)
                    Contoh/Example
                                                           P                                     K
                                      A
                                                              11.2 rad
                                  8.2 cm                         O                                      8.5 cm

                                   1.2 rad                        2.3 rad
                                O
                                                                                            1.5 rad
                                                                                        O
                                         B
                                                                                                        L
                                                             Q  2.3                     r(1.5) = 8.5
                   1.2 rad =  1.2  × 360°               2.3 rad =  2π   × 360°              r = 5.67 cm
                           2π                                 = 131.78°                 1.5 rad =  1.5  × 360°
                         = 68.75°                      Panjang perentas PQ                      2π
                   Panjang perentas AB                      2    2       2                     = 85.94°
                   Length of chord AB                  =  ! 11.2  + 11.2  – 2(11.2)  kos 131.78°  Panjang perentas KL
                                                                                                          2
                                                                                             2
                                                                                                  2
                             2
                        2
                                    2
                   =  ! 8.2  + 8.2  – 2(8.2)  kos / cos 68.75°  = ! 418.034            = ! 5.67  + 5.67  – 2(5.67)  kos 85.94°
                   = ! 85.74                           = 20.45 cm                      = ! 59.745
                                                       Panjang lengkok PQ
                   = 9.26 cm                           = 11.2 × 2.3                    = 7.73 cm
                   Panjang lengkok AB / Length of arc AB  = 25.76 cm                   Perimeter
                   = 8.2 × 1.2                         Perimeter                       = 7.73 + 8.5
                   = 9.84 cm                           = 25.76 + 20.45                 = 16.23 cm
                   Perimeter                           = 46.21 cm
                   = 9.84 + 9.26
                   = 19.1 cm

                         Tip  SPM

                     Gunakan petua kosinus.
                     Use the cosine rule.
                          Tip
                     a  = b + c  – 2bc kos q
                             2
                          2
                      2
                               SPM
                     a  = b + c  – 2bc cos q
                      2
                         2
                            2




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