Page 8 - Modul A+1 Matematik Tambahan Tingkatan 5
P. 8

4.  Hitung perimeter bagi setiap kawasan berlorek.
                     Calculate the perimeter for each of the shaded region.  TP 3

                       Contoh/Example                                  (a)                              P
                                                                                             6.5 cm
                                                D                                     O     0.45 rad
                                           A                                                                             BAB 1
                                       5 cm                                                            Q
                                       O  1.6 rad
                                                                          Perimeter = 6.5 + 6.5 + 6.5(0.45)
                                           B                                      = 13 + 2.93
                                           4 cm                                   = 15.93 cm
                                                C
                       ©PAN ASIA PUBLICATIONS
                       Panjang lengkok AB/Length of arc AB = 5(1.6) = 8 cm
                       Panjang lengkok CD/Length of arc CD = 9(1.6) = 14.4 cm
                       Perimeter kawasan berlorek/Perimeter of the shaded region
                       = AB + BC + CD + AD
                       = 8 + 4 + 14.4 + 4
                       = 30.4 cm


                      (b)                        S                     (c)                   P
                                                                                                 4 cm   S
                                             P                                                     T
                                        6.2 cm
                                          O
                                         1.8 rad                                          0.5 rad
                                              Q                                     O                Q  3 cm R

                                                  R                             4
                                                                          OP =
                          Panjang lengkok SR = 12.4(1.8)                       0.5
                                          = 22.32 cm                          = 8 cm
                          Panjang lengkok PQ = 6.2(1.8)                   Panjang lengkok SR = 11(0.5)
                                           = 11.16 cm                                      = 5.5 cm
                          Perimeter = 11.16 + 6.2 + 22.32 + 6.2           Perimeter = 3 + 5.5 + 3 + 4 + 4 + 8 + 8
                                  = 45.88 cm                                       = 35.5 cm






                  5.  Hitung jejari, j bagi setiap yang berikut.
                     Calculate the radius, j for each of the following.  TP 4

                       Contoh/Example                                  (a)                         Q


                                             1
                                             — rad
                                          T  5      O
                                     V                                                     13 cm
                                               j                                                    8 cm
                                           U
                                      W                                                 1.2 rad

                       Perimeter rantau berlorek = 20 cm                                   O    j   P
                       Perimeter of the shaded region = 20 cm
                       VT = WU = 5 cm                                      Perimeter rantau berlorek = 22.4 cm
                           1
                               1
                       5 +   j +   ( j + 5) + 5 = 20                       Perimeter of the shaded region = 22.4 cm

                           5   5
                                       2  j = 9                             1.2j + (13 – j) + 8 = 22.4
                                       5                                        1.2j – j + 21 = 22.4
                                         j =  45                                       0.2j = 1.4
                                            2                                             j = 7 cm
                                          = 22.5 cm



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         01 Modul Series MateTam Tg5.indd   5                                                                     04/10/2021   2:15 PM
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