Page 20 - 1202 Question Bank Mathematics Form 5
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Answers                                              Complete Answers (Paper 1)

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              CHAPTER 1                               ! m = 12                      (c)  when h = 16
                                                       m = 144                         Q = 6h + 4
                          Paper 1                        1                             Q = 6(16) + 4
                                                           2
                                                 4.  (a)  V =   πr h
                1.  A    2.  D   3.  B   4.  C   5.  C   3                             Q = 100
                                                         3V
                6.  B   7.  C   8.  B   9.  C   10.  D  h =  πr 2                      P =   ! 100
               11.  A  12.  C   13.  A  14.  D  15.  B                                     2
                                                         1
               16.  B   17.  C   18.  C   19.  A  20.  D  h fi                          P =  10
                                                         2
               21.  C  22.  A  23.  D  24.  B   25.  B  r                                 2
                     L = ©PAN ASIA PUBLICATIONS
               26.  C   27.  D  28.  B   29.  C  30.  A  (b)  h = 5 when r = 4           = 5
                                                        k
               31.  C   32.  D  33.  B  34.  B   35.  C     h =  r  2             8.  (a)    q fi   p
               36.  D   37.  B  38.  A                  k                                   ! r
                                                      5 =
                                                        4 2                                 kp
                          Paper 2                                                        q =
                                                      h = 5 × 16 = 80                       ! r
                1.  (a)  q fi   1                      h =   80                              k(3)
                       p 3                              4 2                               9 =
                       k                              when  r = 2                           ! 16
                    q =
                       p 3                              80                             9 × 4 = 3k
                                                      h =    = 20
                       k                                2 2                                 36
                    4 =                                                                  k =
                       1 3                       5.  (a)  k =  pm 2                         3
                    k = 4                                n 3                              k = 12
                                                          2
                       4                                8(2 )                             q =  12p
                    q =                            (b)  k =
                       p 3                               4 3                                ! r
                         4                            k =  32                              12(6)
                  (b)  108 =                            64                          (b)    8 =
                         p  3                           1                                   ! r
                         4                            k =
                      3
                      p  =                              2                              8! r  = 72
                         108                             n  3
                         1                         (c)  p =  2m n 2 3 2                  ! r  =  72
                      p  =
                      3
           CHAPTER 1    2.  (a)  w fi  ! y 3 3  3    6.  (a)  p = kq   n = ! 216     9.  (a)  m fi  k 1 y  2
                                                                                            8
                         27

                                                      12 =
                         1
                                                                                         ! r  = 9
                                                         2(3 )
                      p =
                                                                                         r = 9
                                                             3

                                                      12 × 18 = n
                      q = 500
                                                                                         r = 81
                                                            3
                        x
                                                          n = 6
                        kx
                                                                                       m =
                     w =
                                                                                          y
                                                        1
                                                      k =
                                                                                           k
                                                        6
                        k3
                    27 =  ! y 3                         2 = k(12)                      m =  3x – 1
                                                        q
                        ! 4                        (b)  p =                                 k
                                                        6                               2 =
                        k(27)                           72                                3(5) – 1
                    27 =                              x =                                 k
                         2                               6                              2 =
                      k = 2                           x = 12                              14
                                                        y                               k = 28
                        2x 3                          3 =                                     28
                     w =                                6                              hence, m =
                        ! y                           y = 3 × 6                                y
                        2(4) 3                                                      (b)  m =   28
                  (b)  w =                            y = 18                              3x – 1
                        ! 16                                                        (c)  when m = 4
                       2(64)                     7.  (a)  P fi ! Q                            28
                    w =                               P = k! Q                            4 =
                         2                                                                   y
                    w = 32                            P = k! 6h + 4                          28
                                                                                          y =
                        k! m                          P = k! (6 × 10) + 4                    4
                3.  (a)  L =
                         n 2                                                              y = 7
                                                      4 = k! 64                        3x – 1 = 7
                     4  =   k! 64                     4 = 8k
                     5   5 2                          k =  4                             3x = 8 8
                        25 × 4                          8                                 x =
                      k =                                                                    3
                        8 × 5                         k =  1                              x = 2 2
                        5                               2                                    3
                      k =
                        2                             P =  ! Q                   10.  (a)  p fi qr 3
                        5! m                             2                              p = kqr 3
                        2n 2                       (b)  when P = 2                     108 = k(2)(3) 3
                                                            ! Q                        108 = 54k
                       5! 81                             2 =
                  (b)  L =                                  2                              108
                       2(3 )                            ! Q  = 2 × 2                    k =   54
                         2
                       5
                    L =                                 ! Q  = 4                          = 3
                       2                                                                     3
                     15  5! m                            Q =  4 2                       p = 2qr
                  (c)    =                                                          (b)  p = 2qr 3
                     8  2(4 )                            Q = 16
                           2
                                                                                           3
                         15 × 32                      6h + 4 = 16                          p = 2 ( ) (4 ) 3
                     ! m =                              6h = 12                            4
                         8 × 5                                                           = 96
                                                         h = 2
              118
         Answers 1202BS Maths F5.indd   118                                                                  25/01/2022   11:47 AM
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