Page 21 - 1202 Question Bank Mathematics Form 5

(b) The possible assumptions: RM6 500P = RM520 000
ξ
(i) The speed of the river water and W Z 520 000
the speed of the motorboat are Y P = 6 500
constant all the time. = 80
(ii) The friction between the 10. The balance of red balls
motorboat and the surface of = 131 – 45 6
6
river water, the friction with the 5. (a) x + 3y = 8 = 42
6
air are ignored. When x = 2, 2 + 3h = 8, = 4 × 6 + 2
3h = 8 – 2, = 26
10
SPM ASSESSMENT 3h = 6 The balance of blue balls
h = 2
Paper 1 = 54 – 35 6
6
1. C 2. A 3. B 4. C 5. D (b) Point on x-axis, y = 0 = 15 6
x + 3(0) = 8
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6. D 7. A 8. B 9. C 10. D x = 8 = 1 × 6 + 5
11. D 12. C 13. C 14. C 15. B Coordinate of the point = (8, 0) = 11
10
16. B 17. D 18. A 19. C 20. B Section B
21. B 22. D 23. C 24. A 25. B Gradient of two points = 12 – 0 = 3
26. B 27. C 28. A 29. D 30. C 12 – 8 11. (a) x + y < 160
2
31. D 32. C 33. A 34. C 35. B y = mx + c y > x
36. C 37. B 38. C 39. A 40. B 0 = 3(8) + c 3
c = –24 8x + 5y > 400
Paper 2 hence, the equation of the straight (b) y
Section A line is y = 3x – 24 180
The three inequalities that satisfy the
1. (a) True shaded region: 160
(b) Not a statement x + 3y > 8, y , x, y > 3x – 24 140 x + y = 160
(c) y = 6x + 3 120
2
6. The nearest road that travelled by Ahmad
2. (a) The distance from Mantin to Kajang = 4 + 3 + 8 + 8 = 23 km 100 2
= 70 – 25 = 45 km The nearest road that travelled by Muthu 80 y = –x
3
Time taken from Mantin to Kajang = 11 + 5 + 12 = 28 km 60
= t – 25 Ahmad will reach the library first. 40
Distance
Speed = = 1.5 km min With the the same average speed, it will 20 8x + 5y = 400
–1
Time 0 x
45 = 1.5 take less time for Ahmad to travel. 20 40 60 80 100120140160
t – 25 7. (a) Income = RM3 500, (c) 25 chairs of type A.
45 = 1.5(t – 25) Total expenses (d) When 80 chairs of type A are sold,
45 = 1.5t – 37.5 = 500 + 300 + 1 500 the maximum number of chair of
45 + 37.5 = 1.5t = RM2 300 type B is 80. CHAPTER 8 – SPM Assessment
1.5t = 82.5 Cash flow = RM3 500 – RM2 300 Profit = 8x + 5y
82.5 = RM1 000
t = = 8(80) + 5(800)
1.5 (c) Monthly surplus = RM1 000 + RM600 = 640 + 400
= 55 minutes = RM1600 = RM1 040
(b) Time taken = t – 25 Extra expenses = RM2 500
= 55 – 25 Cash flow = RM1 600 – RM2 500 12. (a) Total income = RM95 560
= 30 min = –RM900 Total tax relief, W
(c) Total distance = 70 km, Total time The cash flow of Encik Faizal = RM9 000 + RM2 500 + RM2 000
taken = 55 min become negative and has a deficit of + RM5 680 + RM3 000
70 km RM900. The cash deficit occurred = RM22 180
Average speed =
55 min because the expenses of Encik Faizal Chargeable income, X
70 km is more than the total income earned. = RM95 560 – RM22 180
= = RM73 380
( ) hour 8. (a) L fi j fi s Tax on the first 70 000, Y
55
60
L = kjs
70 × 60 = RM4 600
= km j 120 = k(2.5)(8)
–1
55 120 Tax on the next balance, Z
= 76.36 km j k = 2.5 × 8 = 6 = (RM73 380 – RM70 000) × 21%
–1
3. (a) A = Ahmad, B = Borhan, C = Chong, L = 6js, = RM3 380 × 21
D = Devi, E = Eliana L = 6(3)(9) 100
= RM709.80
S = {ABC, ABD, ABE, ACD, ACE, = 162 cm 2 (b) Income tax payable
ADE, BCD, BCE, CDE} (b) The curved surface area will
(b) (i) Consist of two female = {ADE, decrease. = Tax on the first 70 000 + tax on the
next balance (3380 × 21%) – Zakat
BDE, CDE} 9. Amount of required insurance = RM4 600 + RM709.80 – RM500
3 1 P
Probability = = = × RM6 500 = RM6 500P = RM4 809.80
9 3 100
(ii) Borhan and Chong together = Amount of compensation (c) Income tax payable in the assessment
{ABC, BCD, BCE} year = RM4 809.80
Probability of Borhan and = Amount of required insurance × Total deduction of PCB
1 Amount of required insurance = RM328 × 12
Chong not together = 1 – 3 RM299 885
2 = RM3 936
= RM450 000 Total of PCB deduction < total
3 = × RM350 000 – RM3 000
4. (a) (i) ξ = P  Q  R RM6 500P income tax payable
(ii) R  Q (set R is the subset for set Amount of required insurance, The balance of the income tax
Q) RM450 000 × RM350 000 payable
(b) W = {3, 6, 9, 12, 15, 18} RM6 500P = RM299 885 + RM3 000 = RM4 809.80 – RM3 936
Y = {1, 2, 4} = RM520 000 = RM873.80
Z = {1, 2, 4, 8}
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Answers 1202BS Maths F5.indd 133 25/01/2022 11:47 AM