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MODUL • Fizik TINGKATAN 5



                   Kesan medan elektrik ke atas cas / Effects of an electric field on charges


                     Bekalan kuasa voltan lampau tinggi (VLT) dihidupkan. Bola   Bekalan  kuasa  VLT dihidupkan.  Terangkan  apa  akan
                     pingpong dibawa bersentuhan dengan plat X dan dilepaskan.   berlaku kepada nyalaan api lilin selepas beberapa ketika.
                     Terangkan apa yang akan berlaku kepada bola pingpong itu.   EHT power supply is turned on. Explain what will happen to
                     Extra high tension (EHT) power supply is turned on. Ping-pong   the candle flame after a while.
                     ball brought into contact with plate X and released. Explain what   Bekalan kuasa voltan
                     will happen to the ping-pong ball.                   lampau tinggi (VLT)
                                                                          Extra high tension   Api lilin
                                       Benang nilon                       power supply (EHT)  Candle flame
                     Bekalan kuasa voltan   Nylon thread
                     lampau tinggi (VLT)
                     Extra high tension     Plat X
                     power supply (EHT)     Plate X
                                                         Bola pingpong                                        Lilin
                                                         yang disaluti                                        Candle
                                                         cat logam                   –
                                                         Ping-pong ball        +
                                                         coated with
                                                         metallic paint
                          +     –                                         •  Molekul udara di ionkan oleh haba daripada nyalaan
                                           Plat Y                           lilin. / The molecules are ionised by heat of the flame.
                                           Plate Y                                                                             UNIT 2
                                                                                           +        -
                     •  Bola pingpong menyentuh plat X, ia dicaskan positif.  Plat terminal   +     -      Plat terminal
 UNIT 2
                       Ping-pong ball touches the plate X, it is positively charged.  negatif  +    -      positif
                                                                               Negative
                     •  Cas positif yang sama menolak bola pingpong ke plat   terminal plate  +     -      Positive
                                                                                                           terminal plate
                       Y. The same positively charge repels the ping-pong balls to
                       plate Y.                                           •  Menghasilkan ion positif dan ion negatif.
                     •  Bola pingpong menyentuh plat Y, ia dicaskan negatif.  Produces positive and negative ions.
                       Ping-pong ball touches the plate Y, it is negatively charged.  •  Jisim ion positif molekul udara > jisim ion negatif
                     •  Cas negatif yang sama menolak                       molekul udara.  / Mass of positive ions of air molecules
                       bola pingpong ke plat X.                             > mass of negative ions of air molecules.
                       The same negatively charge repels                  •  Ion-ion positif molekul udara ditarik ke plat negatif
                       the ping-pong balls to plate X.   Video              dengan perlahan. / The positive ions of air molecules are
                     •  Bola pingpong berayun secara                        pulled towards the negative plate slowly.
                       berterusan di antara plat X dan                    •  Ion-ion negatif molekul udara ditarik ke plat positif
                       plat Y.                                              dengan cepat. / The negative ions of air molecules are
                       The ping-pong ball oscillates                        pulled towards the positive plate faster.
                       continuously in between plate X                    •  Nyalaan lilin terbahagi kepada dua bahagian berlainan
                       and plate Y.                     Medan Elektrik      saiz. / Flame of candle splits into two parts of different
                                                         Electric Field
                                                     https://goo.gl/rymXdV  sizes.




                   Latihan / Exercise

                 1  Bateri sebuah kereta boleh membekalkan arus sebanyak          2  Arus  2 A mengalir melalui  perintang. Apakah bilangan
                     6  A dalam masa 3 jam. Berapakah jumlah cas yang      elektron yang mengalir melalui perintang dalam masa 5
                     disimpan di dalam bateri?                             saat? (cas elektron = 1.6 × 10  C)
                                                                                                  –19
                     A car battery can supply a current of 6 A for 3 hours. What is   A current of 2 A flows through a resistor. What is the number of
                     the amount of charge stored in the battery?           electrons that have passed through the resistor in 5 seconds?
                     Penyelesaian / Solution                               (electron charge = 1.6 × 10 –19  C)
                                                                           Penyelesaian / Solution
                     Q = It = 6 A × (3 × 60 × 60 s)
                             = 64 800 C                                    Q = It, Q = ne
                                                                           It = ne
                                                                           n =   2 A × 5 s   = 6.25 × 10 19
                                                                              1.6 × 10 –19  C
                                                                           \ Bilangan elektron / No. of electrons = 6.25 × 10 19




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