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THEOREM 5.5.5
If A and B are row equivalent matrices, then
(a) A given set of column vectors of A is linearly independent if and only if the corresponding column vectors of B are
linearly independent.
(b) A given set of column vectors of A forms a basis for the column space of A if and only if the corresponding column
vectors of B form a basis for the column space of B.
The following theorem makes it possible to find bases for the row and column spaces of a matrix in row-echelon form by
inspection.
THEOREM 5.5.6
If a matrix R is in row-echelon form, then the row vectors with the leading 1' s ( the nonzero row vectors) form a basis for the
row space of R, and the column vectors with the leading 1' s of the row vectors form a basis for the column space of R.
Since this result is virtually self-evident when one looks at numerical examples, we shall omit the proof; the proof involves little
more than an analysis of the positions of the 0's and 1's of R.
EXAMPLE 5 Bases for Row and Column Spaces
The matrix
is in row-echelon form. From Theorem 5.5.6, the vectors
form a basis for the row space of R, and the vectors
form a basis for the column space of R.

